- #1
darryw
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Homework Statement
I just finished solving about 10 different DEs, but this one has me totally confused. It says:
(R)dQ/dt + (Q/C) = 0, with initial condition Q(0) = Q_0?
Most of the problems I've done thus far have looked like: y' + (2/t)y = (cost)/(t^2), with initial cond y(pi) = 0 and t>0 for example.
So then the RdQ/dt problem is confusing me. I mean, dQ, dt, R, C and Q.. How am I supposed to solve this? Please clarify what they are asking.. I can do these problems but there seems to be 3 variables in this problem?? please help, thanks
Also, shouldn't the correct notation put the R in front of dQ/dt? so it should look like dQ/dt (R) + Q(1/C) = 0 ??
Homework Equations
Specifically, if you could show me how this: (R)dQ/dt + (Q/C) = 0 , is similar to this: y' + p(x)y = q(x) .. I know that y' is the same thing as dy/dx, so is dQ/dt the same as saying Q' ? and if so, then R is the variable right? If that is true then what is C??
The Attempt at a Solution
Homework Statement
Homework Equations
The Attempt at a Solution
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