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Completeness of basis in quantum mechanics
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[QUOTE="wowowo2006, post: 4869357, member: 361949"] In a QM course, I learn that an operator can be represented by basis vectors If the basis vector is complete, the following relation holds There exist coefficient Mij such that Sigma Mij |i > < j|. = I , |i> is the basis! and I is the identity matrix But isn't that in linear algebra We call the set of basis is complete when Any vector can be expressed into their linear combination I wonder why here we seems have 2 definition of completeness [/QUOTE]
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Completeness of basis in quantum mechanics
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