Complex conjugate of absolute exponential

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vg8open
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Hello all,

I am trying to figure out how to solve for the complex conjugate of the following: (-0.5)^abs(x)

Thanks for your help.

-Brian
 
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vg8open said:
Hello all,

I am trying to figure out how to solve for the complex conjugate of the following: (-0.5)^abs(x)

Thanks for your help.

-Brian

abs(x), usually denoted |x|, is a nonnegative real number whether x is real or complex.

So your expression is real. Which makes its conjugate very easy to compute!
 
SteveL27 said:
abs(x), usually denoted |x|, is a nonnegative real number whether x is real or complex.

So your expression is real. Which makes its conjugate very easy to compute!

Not necessarily. What if x=1/4?
 
Char. Limit said:
Not necessarily. What if x=1/4?

Oops missed the minus sign. Thanks.
 
vg8open said:
Hello all,

I am trying to figure out how to solve for the complex conjugate of the following: (-0.5)^abs(x)

Thanks for your help.

-Brian

It's a whole lot easier if you put it into complex exponential, or even better, cos + i sin notation.
 
Char. Limit said:
It's a whole lot easier if you put it into complex exponential, or even better, cos + i sin notation.

I think I missing something here... Are you talking about these equations?
[tex]a^b = e^{(\ln(r) + \phi i)b}[/tex] and [tex]e^{ix} = \cos(x) +i\sin(x)[/tex]
 
Well, by complex exponential, I just mean putting it into r e^(i theta) for some theta and r. But the cos + i sin notation I was talking about, yeah, you got it.