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Complex conjugate of absolute exponential

  1. Feb 13, 2012 #1
    Hello all,

    I am trying to figure out how to solve for the complex conjugate of the following: (-0.5)^abs(x)

    Thanks for your help.

    -Brian
     
  2. jcsd
  3. Feb 13, 2012 #2
    What is the definition of complex conjugation?? Try to apply that first on your expression.
     
  4. Feb 13, 2012 #3
    abs(x), usually denoted |x|, is a nonnegative real number whether x is real or complex.

    So your expression is real. Which makes its conjugate very easy to compute!
     
  5. Feb 13, 2012 #4

    Char. Limit

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    Not necessarily. What if x=1/4?
     
  6. Feb 14, 2012 #5
    Oops missed the minus sign. Thanks.
     
  7. Feb 14, 2012 #6

    Char. Limit

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    It's a whole lot easier if you put it into complex exponential, or even better, cos + i sin notation.
     
  8. Feb 14, 2012 #7
    I think I missing something here... Are you talking about these equations?
    [tex] a^b = e^{(\ln(r) + \phi i)b} [/tex] and [tex]e^{ix} = \cos(x) +i\sin(x) [/tex]
     
  9. Feb 14, 2012 #8

    Char. Limit

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    Well, by complex exponential, I just mean putting it into r e^(i theta) for some theta and r. But the cos + i sin notation I was talking about, yeah, you got it.
     
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