Likemath2014
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How can we show that the following equation has infinitely many solutions
e^z-z^2=0.
Thanks
e^z-z^2=0.
Thanks
The equation ez - z2 = 0 has infinitely many solutions due to the periodic nature of the exponential function ez. By rewriting the equation as z2 = e2 log z, we derive the form e{z - 2 log z} = 1. This leads to the conclusion that the solutions can be expressed as z - 2 log z = 2πn, where n is an integer. The Lambert W function is identified as a useful tool for solving this equation.
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