Complex function, principal value notation

  • Context: Undergrad 
  • Thread starter Thread starter Hill
  • Start date Start date
  • Tags Tags
    Complex function
Click For Summary
SUMMARY

The discussion centers on the interpretation of the principal value notation in complex functions, specifically regarding the logarithmic function. The consensus is that the function Log returns the principal value, while log() represents a multi-valued function. The equation log(z) = ln |z| + i (Arg(z) + 2πk) for k ∈ ℤ illustrates the multi-valued nature of log. The square brackets in the equation Log(z^2) = log([z]^2) are questioned, with participants clarifying that they do not denote principal values for single-valued functions.

PREREQUISITES
  • Understanding of complex functions and their properties
  • Familiarity with logarithmic functions in complex analysis
  • Knowledge of principal values and multi-valued functions
  • Basic grasp of notation in mathematical expressions, particularly square brackets
NEXT STEPS
  • Study the properties of complex logarithms and their principal values
  • Learn about the implications of multi-valued functions in complex analysis
  • Investigate the role of notation in mathematical expressions, focusing on square brackets
  • Explore the concept of argument functions and their applications in complex numbers
USEFUL FOR

Mathematicians, students of complex analysis, and anyone seeking to clarify the nuances of logarithmic functions and principal values in complex mathematics.

Hill
Messages
772
Reaction score
599
TL;DR
Notations ##Log##, ##[]##
When a variable in ##[\text { } ]## means its principal value, ##(-\pi,\pi]##, which is correct:
##Log(z^2)=log([z]^2)## or ##Log(z^2)=log([z^2])## (both, neither)?
 
Physics news on Phys.org
IMO, you are confused. It is the Log that returns the principle value, no matter what the input is. Also, regardless of what the input is, log() does not indicate the principle value. It is a multi-valued function.
## log( z) = ln |z| + i (Arg( z) + 2\pi k)## for ##k \in \mathbb I##.
So the right sides of your two alternative equations are multiple valued.
 
FactChecker said:
IMO, you are confused. It is the Log that returns the principle value, no matter what the input is. Also, regardless of what the input is, log() does not indicate the principle value. It is a multi-valued function.
## log( z) = ln |z| + i (Arg( z) + 2\pi k)## for ##k \in \mathbb I##.
So the right sides of your two alternative equations are multiple valued.
Thank you. This exercise is the source of my confusion:

1698812854299.png


What is a role of the square brackets in the first equation? They cannot mean principal values of ##z^2## and of ##(-z)^2## as these functions are single-valued.
 
@Hill , can you please explain the meaning of '[]'? Is it anything other than a placeholder?
 
WWGD said:
@Hill , can you please explain the meaning of '[]'? Is it anything other than a placeholder?
This is how it appears in the text:

1698814694007.png
 
IMO, regardless of whether ##[z^2]## has the principle argument, ##Arg(z^2)##, the function ##log [z^2]## is multiple valued.
 
  • Like
Likes   Reactions: Hill

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K