Complex Line Integral Value for Natural Numbers n=1,2,3..

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burak100
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I can't find the value, for natural number [itex]n = 1, 2, 3, ...[/itex]
[itex]I = \int\limits_{C}\dfrac{e^{iz}}{z^n} dz[/itex]

find the value. where [itex]z(t) =e^{it}[/itex] , [itex]0\leq t \leq 2\Pi[/itex]
 
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Have you considered applying Cauchy's integral formula,
[tex]f^{(n)}(z)= \frac{1}{2\pi i}\oint_C \frac{f(z)}{(z- a)^{n+1}} dz[/tex]
where C is any closed path containing a?
What is f(z)? What is a?
 
I didn't apply, but in the question f(z) is not given, and also a.
can we choose as f(z)=e^{iz} and a=0 ?
 
sorry for mistake
f(z)=e^{iz} --------> f(z)=e^{it} .