Complex Line Integral Value for Natural Numbers n=1,2,3..

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Discussion Overview

The discussion revolves around evaluating the complex line integral \( I = \int\limits_{C}\dfrac{e^{iz}}{z^n} dz \) for natural numbers \( n = 1, 2, 3, \ldots \), where the contour \( C \) is defined by \( z(t) = e^{it} \) for \( 0 \leq t \leq 2\pi \). The focus is on the application of complex analysis techniques, particularly Cauchy's integral formula.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in finding the value of the integral for natural numbers \( n \).
  • Another participant suggests considering Cauchy's integral formula and questions the choice of \( f(z) \) and \( a \).
  • A participant proposes using \( f(z) = e^{iz} \) and \( a = 0 \) as potential choices for the application of the formula.
  • A later reply corrects the earlier statement about \( f(z) \), clarifying it as \( f(z) = e^{it} \).

Areas of Agreement / Disagreement

Participants do not reach a consensus on the application of Cauchy's integral formula, as there is uncertainty regarding the definitions of \( f(z) \) and \( a \). The discussion remains unresolved.

Contextual Notes

There are limitations regarding the definitions of \( f(z) \) and \( a \), which are not explicitly provided in the original question. The implications of these choices on the evaluation of the integral are not fully explored.

burak100
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I can't find the value, for natural number [itex]n = 1, 2, 3, ...[/itex]
[itex]I = \int\limits_{C}\dfrac{e^{iz}}{z^n} dz[/itex]

find the value. where [itex]z(t) =e^{it}[/itex] , [itex]0\leq t \leq 2\Pi[/itex]
 
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Have you considered applying Cauchy's integral formula,
[tex]f^{(n)}(z)= \frac{1}{2\pi i}\oint_C \frac{f(z)}{(z- a)^{n+1}} dz[/tex]
where C is any closed path containing a?
What is f(z)? What is a?
 
I didn't apply, but in the question f(z) is not given, and also a.
can we choose as f(z)=e^{iz} and a=0 ?
 
sorry for mistake
f(z)=e^{iz} --------> f(z)=e^{it} .
 

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