Can You Distribute 20 lbs of Pressure Oddly Across 5 Hours?

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SUMMARY

The mathematical puzzle of distributing 20 lbs of pressure across 5 hours using only odd numbers reveals that a solution is impossible if zero is excluded. The discussion confirms that two odd numbers always sum to an even number, making it impossible to achieve an odd total of 20 lbs with five odd integers. However, if zero is permitted as a value, a potential solution exists: 17 lbs in the first hour, followed by 1 lb in the next three hours, and 0 lbs in the last hour. Ultimately, the consensus is that without zero, the problem has no valid solutions.

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Complex Mathematical Puzzle!

Distribute 20 lbs of pressure in 5 hours, the numbers Must be Odds and each hour must have a value; you can't use even numbers, nor frations, just positives completes!

which are the values??
 
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Well technically 0 is a value, so

hour 1 = 17
hour 2 = 1
hour 3 = 1
hour 4 = 1
hour 5 = 0.

If 0 is not counted then there is no real solutions.
 


two odds always make an even. 2n+1 + 2n+1 = 4n+2. Since any integer 2n is always even, 4n is also always even. And any even number plus 2 is always even. This also implies 4 odds always make an even.

Then to add an odd to the even number makes it odd

Thus this problem has no solution.

If 0 is acceptable then it has a few solutions.
 


Zero isn't odd in any system of defining 'odd' I've ever heard of. I'm not sure what the point of this problem is. Anybody have any idea?
 


The answer is you can't
 

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