Complex Number Question - Euler's Formula?

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Homework Help Overview

The discussion revolves around expressing the complex number (-2 + 2i) raised to the 10th power in the form re^(iθ), utilizing Euler's Formula. Participants are exploring the conversion of complex numbers into polar form and the implications of raising these forms to a power.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the modulus and argument of the complex number, questioning the steps taken to raise r and θ to the power of 10. There is also inquiry into the simplification of the angle resulting from this operation.

Discussion Status

Some participants have provided guidance on the necessary steps to raise r and θ to the power of 10 and to simplify the resulting angle. Multiple interpretations of the angle's representation are being explored, indicating a productive exchange of ideas.

Contextual Notes

There is mention of the need to reduce angles to a smaller equivalent within the context of polar coordinates, as well as the conventions used in expressing angles in polar form.

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Complex Number Question - Euler's Formula?

Homework Statement



Express (-2 + 2i)^10 in the form re^(iθ)

Homework Equations



Euler's Formula, I think?

The Answer given is: (2√2)^10 e^[i(15pi/2)]

The Attempt at a Solution

I don't know what I'm doing wrong here;

r = √[(-2)^2 + 2^2] = √8 = 2√2theta = pi - arctan (y/x)

= pi - arctan (2/-2)

= pi - 45

= pi - (pi/4)

= 3pi / 4Help will be appreciated. Thanks
 
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Well for one thing you didn't raise your r and theta to the power of 10.

(re^(ix))^10= r^10(e^(i(10x)). Your next step should be to reduce 10x to a smaller angle since angles repeat after 2pi.

Hope that helps.

If you need more explainatiom post again. :-):-)
 


╔(σ_σ)╝ said:
Well for one thing you didn't raise your r and theta to the power of 10.

(re^(ix))^10= r^10(e^(i(10x)). Your next step should be to reduce 10x to a smaller angle since angles repeat after 2pi.

Hope that helps.

If you need more explainatiom post again. :-):-)
Thanks for the reply mate.

So I have to raise r and theta to ^10.

That makes r = (2√2)^10

However how did theta become 15pi/2 ?
 


I think I got it.

Just bring down 10 as the power??

e^[10 x i(3pi/4)]
 


Yes and then simplify the angle. For example 7pi is the same as pi + 2(3)pi.

The answer you gave is correct but was not put in the "best" way.

So 10/4(3pi) = 15pi/2 = 7pi + pi/2 = 6pi + 3pi/2

Angles in polar form are usually written as i( theta + 2npi) :-)

We usually do not put the 2npi part since it is "implied" thus, your answer should be

e^(i 3/2(pi))
 


╔(σ_σ)╝ said:
Yes and then simplify the angle. For example 7pi is the same as pi + 2(3)pi.

The answer you gave is correct but was not put in the "best" way.

So 10/4(3pi) = 15pi/2 = 7pi + pi/2 = 6pi + 3pi/2

Angles in polar form are usually written as i( theta + 2npi) :-)

We usually do not put the 2npi part since it is "implied" thus, your answer should be

e^(i 3/2(pi))
OH!

I understand now. Thanks heeps for the help.
 

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