Complex exponentials - homework

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Homework Help Overview

The discussion revolves around finding a complex number \( z = a + i*b \) such that the real part of \( e^{z*t} \) equals \( \cos(2\pi t) \). Participants are exploring the relationship between complex exponentials and trigonometric functions.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster begins by expressing \( e^{(a+i*b)*t} \) and equating the real part to \( \cos(2\pi t) \). Some participants question whether \( t \) is a real variable and suggest finding values for \( a \) and \( b \) based on the equation \( e^{at}\cos(b) = \cos(2\pi t) \).

Discussion Status

Participants are actively engaging with the problem, offering hints and confirming the real nature of \( t \). Some guidance has been provided regarding the relationship between the terms, but there is no explicit consensus on the values of \( a \) and \( b \).

Contextual Notes

There is an emphasis on understanding the implications of \( t \) being a real variable, and participants are navigating the constraints of the problem without providing direct solutions.

Poetria
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Could you give me a hint how to attack this problem?

Find a complex number z = a+i*b such that f(t)=Re e^(z*t) where f(t)=cos(2*pi*t)

I have begun as follows:

e^((a+i*b)*t)=e^(a*t)*(cos(b)+i*sin(b))

Re e^(z*t)= e^(a*t)*cos(b)

What to do now?
 
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Hi, ##t## is real? If is yes so you must find ##a,b## from ##e^{at}\cos{b}=cos(2\pi t)## ...
 
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Ssnow said:
Hi, ##t## is real? If is yes so you must find ##a,b## from ##e^{at}\cos{b}=cos(2\pi t)## ...

Yes, t is a real variable.I know I must but how? Thank you very much. :)
 
another hint: ## e^{at}cos{(b)}=e^{0t}cos{(2\pi t)}##, you can read now ##a=...## and ##b=...##
 
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Ssnow said:
another hint: ## e^{at}cos{(b)}=e^{0t}cos{(2\pi t)}##, you can read now ##a=...## and ##b=...##

Ok, I got it. :) Great. Thank you very much. :)
 
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