Complex numbers problems | Solving equations using polar form

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Homework Help Overview

The problem involves solving an equation within the context of complex numbers, specifically focusing on the equation |z| - z = 1 + 2i. The original poster expresses difficulty in manipulating the equation and translating their thoughts into English.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve the equation by assuming a value for y and manipulating the equation, but encounters challenges. Other participants suggest replacing variables with their definitions and equating real and imaginary parts, while also hinting at using polar form.

Discussion Status

The discussion is active, with participants offering hints and alternative methods for approaching the problem. There is a focus on different strategies for dealing with complex numbers, but no consensus or resolution has been reached yet.

Contextual Notes

The original poster mentions a language barrier, which may affect their ability to express their reasoning clearly. Additionally, there are hints provided that suggest familiarity with polar form and the use of specific mathematical notation.

Broken Steel
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Homework Statement


Solve the equation in the complex numbers set (this is as best as i could translate since English is not my native language :D)

[tex]\left|z\right|-z=1+2i[/tex]


Homework Equations


|z|=sqrt{x^2+y^2}

z=x+iy

The Attempt at a Solution


Well i started by supposing y=1 and then i get sqrt{x^2+1}-x=1-i+x
i tried to square the whole equation but i end up with nothing.. So what should I do??

Oh and the solution is 3/2 - 2i
 
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Hi Broken Steel! :smile:

(have a square-root: √ and a phi: φ and try using the X2 tag just above the Reply box :wink:)

Hint: re :smile:
 
How about this way?
[tex]\left|z\right|-z=1+2i[/tex]

Replace the |z| and z by the values you specified above:
[tex]\sqrt{x^2+y^2} - (x + yi) = 1 + 2i[/tex]

Remove the parentheses, and then equate the real coefficients and the imaginary coefficients.
 
tiny-tim said:
Hi Broken Steel! :smile:

(have a square-root: √ and a phi: φ and try using the X2 tag just above the Reply box :wink:)

Hint: re :smile:


Likes this method because it is more useful for dealing with complex numbers.

Also, eumyang's is probably a more familiar method.
 

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