Complex series: Circle of convergence

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SUMMARY

The discussion centers on the application of the ratio test for determining the circle of convergence of complex power series represented as ∑_{n=0}^∞ c_n z^n. Participants confirm that the ratio test yields consistent results regardless of index shifts, such as substituting n with n+3. Additionally, it is established that the ratio test is applicable to power series starting from any integer, including n=1 or n=-1, as the convergence is unaffected by a finite number of terms.

PREREQUISITES
  • Understanding of complex power series
  • Familiarity with the ratio test for convergence
  • Knowledge of limits in calculus
  • Basic concepts of series convergence and divergence
NEXT STEPS
  • Study the derivation of the ratio test for power series
  • Explore the monotone convergence theorem and its applications
  • Investigate examples of power series starting from different indices
  • Learn about other convergence tests, such as the root test and comparison test
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Mathematicians, students studying complex analysis, and anyone interested in understanding the convergence of power series.

Niles
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Homework Statement


Hi all.

Lets say I have a complex power series given by

[tex] \sum_{n=0}^\infty c_nz^n,[/tex]

where z is a complex number and c is a complex constant. Inside its circle of convergence, I can differentiate it leading to

[tex] \sum_{n=0}^\infty c_nnz^{n-1} = \sum_{n=0}^\infty (n+1)c_{n+1}nz^{n}.[/tex]

If I want to find the circle of convergence for this series, then I can use the ratio test

[tex] \frac{1}{R} = \mathop {\lim }\limits_{n \to \infty } \left| {\frac{{a_{n + 1} }}{{a_n }}} \right|.[/tex]

I have two questions for this:

Question #1: Does the ratio test give me the same answer regardless of I substitute e.g. n -> n+3? I.e., is it correct that

[tex] \mathop {\lim }\limits_{n \to \infty } \left| {\frac{{a_{n + 1} }}{{a_n }}} \right| = \mathop {\lim }\limits_{n \to \infty } \left| {\frac{{a_{n + 3} }}{{a_{n + 2} }}} \right|.[/tex]

Personally, I think it does not matter, because we let n go to infinity.

Question #2: Does the ratio test only work for power series that go from n=0 to infinity, or do they also work if n start at e.g. 1 or -1?Thank you very much in advance.Niles.
 
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Well the ratio test is typically derived from comparison to a geometric series. Moreover, one way to derive the comparison test is based on the monotone convergence theorem applied to partial sums. So I think you're right on both counts since only long term behavior matters. Especially for question 2, remember that including or excluding a finite number of terms in an infinite series does not affect convergence.
 
Hi Niles! :smile:
Niles said:
Question #1: Does the ratio test give me the same answer regardless of I substitute e.g. n -> n+3? I.e., is it correct that

[tex] \mathop {\lim }\limits_{n \to \infty } \left| {\frac{{a_{n + 1} }}{{a_n }}} \right| = \mathop {\lim }\limits_{n \to \infty } \left| {\frac{{a_{n + 3} }}{{a_{n + 2} }}} \right|.[/tex]

Personally, I think it does not matter, because we let n go to infinity.

Question #2: Does the ratio test only work for power series that go from n=0 to infinity, or do they also work if n start at e.g. 1 or -1?

Your intuitive suspicions are completely correct …

limiting behaviour is only affected "near" the limit …

what happens at the other end doesn't matter!

So yes, to both #1 and #2. :smile:
 

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