Components of metric perturbation in TT gauge

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SUMMARY

This discussion focuses on the derivation of the relationship between the trace-reversed metric perturbation in the transverse traceless (TT) gauge, specifically transitioning from the equation \bar{h^{TT}_{\mu \nu}} = A^{TT}_{\mu \nu} cos(\omega (t-z)) to h^{TT}_{\mu \nu} = B^{TT}_{\mu \nu} cos(\omega (t-z)). The key equations involved are \bar{h}_{\mu \nu} = h_{\mu \nu} - \frac{1}{2} \eta_{\mu \nu} h and h = h^{\alpha}_{\alpha} = \eta^{\alpha \beta} h_{\alpha \beta}. The participant expresses confusion regarding the condition that leads to \bar{h} = -h, which is essential for the derivation.

PREREQUISITES
  • Understanding of metric perturbations in general relativity
  • Familiarity with the transverse traceless (TT) gauge
  • Knowledge of the Minkowski metric and its properties
  • Basic grasp of tensor notation and manipulation
NEXT STEPS
  • Study the properties of the Minkowski metric in detail
  • Learn about the implications of the transverse traceless (TT) gauge in gravitational wave theory
  • Explore the derivation of trace-reversed metric perturbations
  • Investigate the role of the Einstein field equations in metric perturbations
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This discussion is beneficial for students and researchers in theoretical physics, particularly those focusing on general relativity and gravitational wave physics.

fasterthanjoao
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Homework Statement



I'm just working through a textbook and there's a line in which I'm clearly missing something. What I want to do is show that from:
\bar{h^{TT}_{\mu \nu}} = A^{TT}_{\mu \nu} cos(\omega (t-z)) [\tex]<br /> to<br /> h^{TT}_{\mu \nu} = B^{TT}_{\mu \nu} cos(\omega (t-z)) [\tex]&lt;br /&gt; &lt;br /&gt; &lt;br /&gt; &lt;h2&gt;Homework Equations&lt;/h2&gt;&lt;br /&gt; &lt;br /&gt; \bar{h}_{\mu \nu} = h_{\mu \nu} - \frac{1}{2} \eta_{\mu \nu} h[\tex]&amp;lt;br /&amp;gt; h = h^{\alpha}_{\alpha} = \eta^{\alpha \beta} h_{\alpha \beta}[\tex]&amp;amp;lt;br /&amp;amp;gt; &amp;amp;lt;br /&amp;amp;gt; &amp;amp;lt;br /&amp;amp;gt; &amp;amp;lt;h2&amp;amp;gt;The Attempt at a Solution&amp;amp;lt;/h2&amp;amp;gt;&amp;amp;lt;br /&amp;amp;gt; &amp;amp;lt;br /&amp;amp;gt; There&amp;amp;amp;#039;s just one line where I have an issue, i think. &amp;amp;lt;br /&amp;amp;gt; &amp;amp;lt;br /&amp;amp;gt; I&amp;amp;amp;#039;ve used the above equations to say:&amp;amp;lt;br /&amp;amp;gt; &amp;amp;lt;br /&amp;amp;gt; \bar{h} = \eta^{\mu \nu}\bar{h}_{\mu \nu}[\tex]&amp;amp;amp;lt;br /&amp;amp;amp;gt; then substituted the equation for \bar{h}_{\mu \nu}[\tex] to get:&amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;gt; &amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;gt; \bar{h} = h - \frac{1}{2} \eta^{\mu \nu} \eta_{\mu \nu} h[\tex]&amp;amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;amp;gt; &amp;amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;amp;gt; which is fine, but for it to work this last line must equal -h[\tex], I think and I&amp;amp;amp;amp;amp;amp;amp;#039;m not sure i see where that comes from.&amp;amp;amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;amp;amp;gt; &amp;amp;amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;amp;amp;gt; thanks.&amp;amp;amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;amp;amp;gt; &amp;amp;amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;amp;amp;gt; ftj
 
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Your eta is the Minkowski metric, right?

eta_{alpha beta} eta^{mu nu} = delta_{alpha}^{mu} delta_{beta}^{nu}

Take it away.
 

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