How Do You Calculate the Velocity of a Stone in Projectile Motion?

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To calculate the velocity of a stone thrown horizontally at 5 meters per second after 0.2 seconds, one must consider both horizontal and vertical components of motion. The horizontal velocity remains constant at 5 m/s, while the vertical velocity can be calculated using the formula v = gt, where g is the acceleration due to gravity (9.8 m/s²) and t is time (0.2 s). This results in a vertical velocity of approximately 1.96 m/s downward. The overall velocity can then be determined using the Pythagorean theorem to combine the horizontal and vertical components. Understanding these principles is essential for solving projectile motion problems effectively.
The Vitruvian Man

Homework Statement


Astone is thrown horizontally with an initial velocity of 5 metres per second. What is the magntude and direction of its velocity 0.2s later? Take the acceleration of free fall to be 9.8 metres per second squared and ignore friction.

Homework Equations

The Attempt at a Solution


This question, I find it very confusing I do not know why..I have no clue.[/B]
 
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Welcome to the forum. Please note the forum rules in the homeworks section require you to make an attempt at a solution so we can see where you are going wrong.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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