Composing Two Complex Functions

  • Thread starter Thread starter Bashyboy
  • Start date Start date
  • Tags Tags
    Complex Functions
Click For Summary
SUMMARY

The discussion focuses on the composition of the complex function f(z) = x + iy² with the contour defined by z(t) = e^t + it over the interval [a, b]. The participants successfully identify x(t) = e^t and y(t) = t, leading to the conclusion that f(z(t)) = e^t + it². The conversation also explores the general case of function composition, confirming that f(x(t), y(t)) = u(x(t), y(t)) + iv(x(t), y(t)) holds true.

PREREQUISITES
  • Understanding of complex functions and their notation
  • Familiarity with parametric equations in calculus
  • Knowledge of function composition in mathematics
  • Basic grasp of complex variables and mappings
NEXT STEPS
  • Study the properties of complex functions, particularly f(z) = x + iy²
  • Learn about parametric equations and their applications in complex analysis
  • Explore the concept of function composition in greater depth
  • Investigate the implications of contour integration in complex analysis
USEFUL FOR

Students and educators in mathematics, particularly those focusing on complex analysis, calculus, and function theory. This discussion is beneficial for anyone looking to deepen their understanding of function composition and parametric representations in complex functions.

Bashyboy
Messages
1,419
Reaction score
5

Homework Statement


Suppose we have the function ##f(z) = x + iy^2## and a contour given by ##z(t) = e^t + it## on ##a \le t \le b##.
Find ##x(t)##, ##y(t)##, and ##f(z(t))##.

Homework Equations

The Attempt at a Solution


Well, ##x(t)## and ##y(t)## are rather simple to identity. However, I am having difficulty determining ##f(z(t))##, which I believe seems from some notational issues.

##f(z) = f(z(t)) = f(\underbrace{e^t + it}_?) = ...?##

I could write

##f(z) = x + iy^2 \iff##

##f\langle (x,y) \rangle = x + iy^2##.

I know that ##x(t) = e^t## and ##y(t) = t##.

##f\langle (x(t), y(t) ) \rangle = x(t) + i[y(t)]^2 \iff##

##f\langle (x(t), y(t) ) \rangle = e^t + it^2##.

I find this somewhat unsettling. Suppose that I have the function ##f(z) = f(x,y) = u(x,y) + iv(x,y)## (I am dropping the ##\langle \rangle## notation); and suppose that we have the contour described by the parametric function ##z(t) = x(t) + iy(t)##. In the general case, would the composition look like

##f(x(t),y(t)) = u(x(t),y(t)) + iv(x(t),y(t))##?
 
Last edited by a moderator:
Physics news on Phys.org
Bashyboy said:

Homework Statement


Suppose we have the function ##f(z) = x + iy^2## and a contour given by ##z(t) = e^t + it## on ##a \le t \le b##.
Find ##x(t)##, ##y(t)##, and ##f(z(t))##.

Homework Equations

The Attempt at a Solution


Well, ##x(t)## and ##y(t)## are rather simple to identity. However, I am having difficulty determining ##f(z(t))##, which I believe seems from some notational issues.

##f(z) = f(z(t)) = f(\underbrace{e^t + it}_?) = ...?##

I could write

##f(z) = x + iy^2 \iff##

##f\langle (x,y) \rangle = x + iy^2##.

I know that ##x(t) = e^t## and ##y(t) = t##.

##f\langle (x(t), y(t) ) \rangle = x(t) + i[y(t)]^2 \iff##

##f\langle (x(t), y(t) ) \rangle = e^t + it^2##.
Looks fine to me. f maps a complex number x + iy to x + iy2, so the same function maps et + it to et + it2, which is what you have.
Bashyboy said:
I find this somewhat unsettling. Suppose that I have the function ##f(z) = f(x,y) = u(x,y) + iv(x,y)## (I am dropping the ##\langle \rangle## notation); and suppose that we have the contour described by the parametric function ##z(t) = x(t) + iy(t)##. In the general case, would the composition look like

##f(x(t),y(t)) = u(x(t),y(t)) + iv(x(t),y(t))##?
 
  • Like
Likes   Reactions: Bashyboy

Similar threads

Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 27 ·
Replies
27
Views
2K
Replies
9
Views
2K
Replies
2
Views
1K
Replies
6
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K