Composite Functions: Determine gof(x) & foh(x)

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The discussion focuses on determining the composite functions gof(x) and foh(x) using the provided functions f(x), g(x), and h(x). The user attempts to calculate gof(x) as g(f(x)) and foh(x) as f(h(x)), but expresses uncertainty about the correctness of their calculations. A key point raised is the misunderstanding of logarithmic and exponential properties, specifically that ln(A+B) does not equal lnA + lnB, and e^(A+B) does not equal e^A + e^B. The user is advised to review their calculations and check their use of parentheses for accuracy.
DJ-Smiles
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Homework Statement


Determine each of the following composite functions:
a) gof(x)
b)foh(x)

Homework Equations


Where f(x)=e^(3x+2) [e is the exponential function]
g(x)= ln(4x+1)
h(x)= 1/(2x-1)

The Attempt at a Solution


So I have found an answer, I am just unsure if I am correct though. This is what I did:

a) gof(x)=g(f(x))
= ln(4(f(x)+1)
=ln(4e^(3x+2)+1)
= ln4e^(3x+2)+ln1
=(3x+2)*4*lne+ln1
= 4(3x+2)+ln1
=12x+8+ln1
=12x+8

b)foh(x)=f(h(x))
=e^(3(h(x))+2)
=e^(3(1/(2x-1))+2)
=e^(3/(2x-1))+2)Is this the correct working out and answers?
 
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DJ-Smiles said:

The Attempt at a Solution


So I have found an answer, I am just unsure if I am correct though. This is what I did:

a) gof(x)=g(f(x))
= ln(4(f(x)+1)
=ln(4e^(3x+2)+1)
[STRIKE]= ln4e^(3x+2)+ln1[/STRIKE]

b)foh(x)=f(h(x))
=e^(3(h(x))+2)
=e^(3(1/(2x-1))+2)
[STRIKE]=e^(3/(2x-1))+2)[/STRIKE]


Is this the correct working out and answers?

Neither the logarithm nor the exponential are additive functions.

ehild
 
what does that mean and how does it affect my final answers?
 
ln(A+B)≠lnA+lnB. eA+B≠eA+B.
Also check your parentheses.


ehild
 

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