Compressed Spring Between Two Boxes

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SUMMARY

The discussion centers on a physics problem involving two blocks of masses M and 2M on a frictionless surface, separated by a compressed spring. Upon release, the block of mass 2M exits the spring with velocity v. The correct answer for the velocity of the center of mass of the system is zero, confirmed through the conservation of linear momentum. The participants emphasize the importance of understanding the center of mass and its relation to the system's motion, drawing parallels to explosive scenarios.

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  • Basic knowledge of calculus for deriving equations
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Soniteflash
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Homework Statement


Two blocks of masses M and 2M are on a frictionless horizontal surface and are held in place with a compressed spring of negligible mass between them. If the blocks are then released and the block of mass 2M leaves the spring with a velocity v, the velocity of the center of mass of the blocks is

A zero
B -(v/2)
C -(2v/3)
D -(3v/2)
E -2v

Homework Equations


n/a ?

The Attempt at a Solution


I do not understand how the center of mass relates to the movement of the blocks. I remember from class that if an object exploded into thousands of pieces the center of mass would still be at the original position.
So I assume it is A. Zero.
 
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Soniteflash said:
I do not understand how the center of mass relates to the movement of the blocks. I remember from class that if an object exploded into thousands of pieces the center of mass would still be at the original position.
So I assume it is A. Zero.

Can you explain why it would be zero? I mean, you are right. But it might be beneficial to examine the problem a little more deeply.
 
AlephNumbers said:
Can you explain why it would be zero? I mean, you are right. But it might be beneficial to examine the problem a little more deeply.
I am not quite sure but I thought it is similar or identical sort of to an explosion.
 
It is very similar to an explosion. Try using conservation of linear momentum and the equation for the velocity of the center of mass of a system of particles (or blocks, in this case) to show why your answer is correct.
 
For linear momentum :
Pi=Pf
0 = m(-2v) + (2mv)
0 = -2mv + 2mv
0 = 0
Linear momentum is conserved.

Hmm, I don't really know an equation for the velocity of the center of mass of a system of particles. I know that the velocities of the boxes are both in opposite directions.
 
It isn't too difficult to prove.

Start with the equation for the center of mass of a system of particles. If you don't know that either, you can find it here http://hyperphysics.phy-astr.gsu.edu/hbase/cm.html.

Any ideas on what you can do to this equation to create an equation for the velocity of the center of mass?
It involves calculus.
 

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