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athrun200
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Homework Statement
If the total energy of the electron E>>m[itex]c^{2}[/itex]
Prove that the formula of wavelength would be
[itex]\lambda '[/itex]=[itex]\frac{hc}{E}[/itex](1+[itex]\frac{m^{2}c^{4}\lambda}{4hcE}[/itex])
where [itex]\lambda '[/itex] is the wavelenght after scattering
m is the mass of electron
Homework Equations
The Attempt at a Solution
I have proved that [itex]\lambda '[/itex]=[itex]\frac{\lambda(E-Pc)+2hc}{E+Pc}[/itex]
In my equation, P is the initial momentum of the electron.
I haven't use the given assumption E>>m[itex]c^{2}[/itex]. So we must use it to eliminate P.
But if E>>m[itex]c^{2}[/itex][itex]\Rightarrow[/itex] E[itex]\approx[/itex]Pc
this cannot get the answer