Compton Scattering: Solving for E with $\phi = 1/4\pi$

[Pushoam]

Homework Statement

Homework Equations

The Attempt at a Solution

$\lambda' = 2 \lambda$

$\lambda' - \lambda = \lambda = \frac { h} { mc} \cos{ \phi }$

Here, $\phi = \frac { pi} 4$ is the angle between photon's original line of motion and its line of motion after scattering.

Putting the values, I got E = $\frac { hc} {\lambda }$ = 1.75 MeV, i.e. option (a).

Is this correct?
[/B]

 

[kuruman]

The Compton scattering equation is incorrect, but the answer is (surprisingly) correct. ?

 

[PSRB191921]

Hi
I have the same result (Ei=1.75 MeV) if I consider the Compton relationship$$E_{s}=\frac{E_{i}}{1+\frac{E_{i}}{mc^{2}} \left( 1-cos\theta \right) } $$Es=Ei/2
Sorry kuruman is the fastest

 

[Pushoam]

The Compton scattering equation is incorrect, but the answer is (surprisingly) correct. ?

Because I did the right calculation and wrong typing.
The following is wrong:

$\lambda' - \lambda = \lambda = \frac { h} { mc} \cos{ \phi }$

The correct one is :
$\lambda' - \lambda = \lambda = \frac { h} { mc} ( 1 - \cos{ \phi })$

 

[Pushoam]

Sorry kuruman is the fastest

How did you get to know this? He has not shown the solution.