Computating the components of a tensor

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The discussion focuses on computing the components of a tensor using the duality relation and the expansion of a tensor in terms of basis vectors. Specifically, it highlights that the components of a tensor can be derived by inserting basis vectors into its slots, as demonstrated by the equation Tαβμ = T(𝑒α, 𝑒β, 𝑒μ). The conversation also addresses the distinction between simple tensors and more complex forms, emphasizing that tensors can be sums of tensor products, as noted in Schutz's "Geometrical Methods of Mathematical Physics." The Einstein summation convention is mentioned as a method for simplifying tensor expressions.

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  • Understanding of tensor notation and operations
  • Familiarity with basis vectors and dual spaces
  • Knowledge of the Einstein summation convention
  • Basic concepts of linear algebra and vector spaces
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  • Learn about the construction of tensor products in detail
  • Explore the implications of the Einstein summation convention in tensor calculus
  • Investigate methods for deriving bases for vector spaces associated with tensors
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Rasalhague
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In the first problem here http://elmer.tapir.caltech.edu/ph237/assignments/assignment2.pdf , we're asked to show from the duality relation

\mathbf{e}^{\mu} \cdot \mathbf{e}_{\nu} = \delta^{\mu}_{\nu}

and the expansion of a tensor

\mathbf{T}\left(\underline \quad, \underline \quad, \underline \quad \right)

in terms of basis vectors:

\mathbf{T} = T^{\alpha \beta}_{\mu} \mathbf{e}_{\alpha} \otimes \mathbf{e}_{\beta} \otimes \mathbf{e}^{\mu}

that the components of a tensor can be computed by inserting basis vectors into its slots and lining up the indices, e.g.

T^{\alpha \beta}_{\mu} = \mathbf{T}\left(\mathbf{e}^{\alpha},\mathbf{e}^{\beta}, \mathbf{e}_{\mu} \right).

The solution ( http://elmer.tapir.caltech.edu/ph237/assignments/solutions/week2/page1.jpg ) does just that.

(Note: in these lectures and the accompanying material, Kip Thorne avoids making an explicit distinction between one-forms and vectors, by associating one-forms with vectors via the metric tensor.)

What puzzles me is that I read (in Schutz: Geometrical Methods of Mathematical Physics) that a tensor isn't always simply a tensor product; it might be a sum of tensor products. So does this proof only apply to simple tensors (those which are tensor products), and if so, what would a general proof look like? Also, is there an easy way to tell whether a given tensor is simple? And is there a way to derive a basis for the vector space a tensor belongs to from the basis of the vector space V in terms of which the tensors are defined?
 
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The tensor T here is a sum of tensor products. The summation sign is omitted by convention, but there is a sum over alpha, beta and mu. This is called the Einstein summation convention.
 
Aha, yes, thanks, dx, for once again coming to my rescue! I see it now: T is a sum of all those permutations of tensor products of the chosen basis vectors of V and its dual space V* (or using this convention whereby vectors are associated with 1-forms via the inner product, the chosen basis of V and the reciprocal basis), each permutation scalar-multiplied by the appropriate component.
 

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