- #1

rayman123

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## Homework Statement

let [tex]f(x)=x^2[/tex] Calculate upper sum and lower sum on the interval [tex][-2,2][/tex] when n=2

## The Attempt at a Solution

since n=2 I divide the interval into

[tex][-2,0]\cup[0,2][/tex]

then on the interval [tex][-2,0][/tex] the function [tex]f(x)=x^2[/tex] has the highest valute at [tex]x=-2, f(-2)=4=M_{0}[/tex] and the lowest value is at [tex] x=0, f(0)=0=m_{0}[/tex]

on the interval the situation is the same [tex]x=0, f(0)=0=m_{1}

[/tex](again the lowest value) ,and at [tex] x=2, f(2)=4=M_{1}[/tex](the highest value)

thus upper sum will be

[tex]S_{n}=M_{0}\cdot \Delta x+M_{1}\cdot \Delta x[/tex] where [tex]\Delta x=2[/tex]

[tex]S_{n}=4\cdot 2+4\cdot 2=16[/tex]

lower sum

[tex]s_{n}=0\cdot 2+0\cdot 2=0[/tex]

and here I am a bit confused cause in my homework it says'' if you calculated correctly then the difference between lower sum and upper sum should be 16'' well here it would not work...where do I make mistake?

any help appreciated