1. The problem statement, all variables and given/known data A 100 kg trunk loaded with old books is to be slid across a floor by a woman who exerts a force of 500 N down and forward at 30° with the horizontal. If μk = 0.3 and μs = 0.4, compute the resulting acceleration. 2. Relevant equations and 3. The attempt at a solution N = mg, of trunk N = 100kg * 9.8 = 980 N Push of lady : N = F sin theta N = 500N * sin 30 = 250N Total force being exerted = 980 + 250N = 1230N friction kinetic force: f = u*N f = .3 * 1230N friction force of moving box = 369N woman pushes with force: 500N * cos 30 = 433N So with 433N force of push - 369N friction = 64N of net force on sliding box Net force = mass * acceleration 64N = 100kg * a acceleration = 0.64 m/s^2 => INCORRECT => Please help!