Compute the torque developed by an airplane engine

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SUMMARY

The torque developed by an airplane engine with an output of 2000 horsepower at an angular velocity of 2400 revolutions per minute is calculated to be 5.937 x 103 N·m. When a drum with a diameter of 0.5 meters is attached to the motor shaft, the maximum weight that can be lifted using the engine's power output is 23.748 x 103 N. To determine the lifting speed of this weight, the relationship v = r * ω is applied, where r is the radius of the drum and ω is the angular velocity in radians per second.

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John O' Meara
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(a)Compute the torque developed by an airplane engine whose output is 2000hp at an angular velocity of 2400 rev/min. (b) If a drum of negligible mass, .5m in diameter, were attached to the motor shaft and the power output of the motor were used to raise a weight hanging from a rope wrapped around the drum, how large a weight could be lifted. (c) At what speed would it lift that weight.
My attempt (a) torque=P/w = 5.937*10^3N.m
(b) F=torque/r = 23.748*10^3N
(c) v=r*w. Any help on how to do part c, would be welcomed, thanks.
 
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John O' Meara said:
(c) v=r*w. Any help on how to do part c, would be welcomed, thanks.
Your equation should work just fine
 

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