How Much Torque Does an Electric Motor Develop at 3000 RPM?

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irun4edmund
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Homework Statement


An electric motor consumes 12.0 KJ of electrical energy in 1.00 min. If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 3000 rpm?


Homework Equations





The Attempt at a Solution


Since one third of the energy is converted to heat only 2/3 contribute to torque or 8.0 KJ

I get P = 8KJ * 60s = 480 * 10^3 W

converting angular speed from rpm to rad/s i get (3000 * 2 pi) / 60s = 314.2 rad/s

since torque = power / angular speed:
T = (480 * 10^3) / 314.2 = 1.37 *10^3

but I am not getting the right answer. any help would be greatly apreciated.
 
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irun4edmund said:

Homework Statement


An electric motor consumes 12.0 KJ of electrical energy in 1.00 min. If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 3000 rpm?


Homework Equations





The Attempt at a Solution


Since one third of the energy is converted to heat only 2/3 contribute to torque or 8.0 KJ

I get P = 8KJ * 60s = 480 * 10^3 W

(I accidentally deleted my last reply.)

I believe here is an error. A Watt is a Joule/second, so power is not the energy multiplied by the time.
 
yup. thanks a lot. Just a silly mistake on my part. Thats what i get for trying to do phyics at 1 am.