How Much Torque Does an Electric Motor Develop at 3000 RPM?

Click For Summary
SUMMARY

An electric motor consuming 12.0 KJ of electrical energy in 1 minute develops torque based on the energy converted to output. With one-third of the energy lost to heat, 8.0 KJ is available for torque generation. The power output is calculated as 480,000 W, and with an angular speed of 314.2 rad/s at 3000 RPM, the torque is determined to be 1.37 x 10^3 N·m. A common mistake in calculations involves misapplying the relationship between power, energy, and time.

PREREQUISITES
  • Understanding of electric motor energy consumption
  • Familiarity with power calculations in physics
  • Knowledge of angular speed conversion from RPM to rad/s
  • Basic principles of torque calculation
NEXT STEPS
  • Study the relationship between power, energy, and time in physics
  • Learn about torque calculations in electric motors
  • Explore the effects of energy loss in electric motor efficiency
  • Investigate the conversion of RPM to rad/s in mechanical systems
USEFUL FOR

Students studying physics, engineers working with electric motors, and anyone interested in understanding torque generation in mechanical systems.

irun4edmund
Messages
14
Reaction score
0

Homework Statement


An electric motor consumes 12.0 KJ of electrical energy in 1.00 min. If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 3000 rpm?


Homework Equations





The Attempt at a Solution


Since one third of the energy is converted to heat only 2/3 contribute to torque or 8.0 KJ

I get P = 8KJ * 60s = 480 * 10^3 W

converting angular speed from rpm to rad/s i get (3000 * 2 pi) / 60s = 314.2 rad/s

since torque = power / angular speed:
T = (480 * 10^3) / 314.2 = 1.37 *10^3

but I am not getting the right answer. any help would be greatly apreciated.
 
Last edited:
Physics news on Phys.org
irun4edmund said:

Homework Statement


An electric motor consumes 12.0 KJ of electrical energy in 1.00 min. If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 3000 rpm?


Homework Equations





The Attempt at a Solution


Since one third of the energy is converted to heat only 2/3 contribute to torque or 8.0 KJ

I get P = 8KJ * 60s = 480 * 10^3 W

(I accidentally deleted my last reply.)

I believe here is an error. A Watt is a Joule/second, so power is not the energy multiplied by the time.
 
yup. thanks a lot. Just a silly mistake on my part. Thats what i get for trying to do phyics at 1 am.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
3K
Replies
6
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
Replies
8
Views
3K
Replies
11
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
4K
  • · Replies 6 ·
Replies
6
Views
1K