Compute Unit Normal Vector: Why Derivative is Orthogonal

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The unit normal vector N of a curve is derived from the first derivative of the unit tangent vector T(t), normalized by the norm of T'(t). The discussion highlights that T(t) is orthogonal to its derivative T'(t), raising questions about the conditions under which this orthogonality holds. It is clarified that this orthogonality is not universally applicable; it specifically occurs when the tangent vectors maintain a constant length. When the length of the tangent vector is constant, the derivative of the length is zero, reinforcing the relationship between T and T'. Understanding these conditions is crucial for comprehending the geometric implications of tangent and normal vectors in calculus.
lordkelvin
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The unit normal vector N of a given curve is equal to the first derivative with respect to t of the unit tangent vector T'(t)divided by the norm of T'(t) (For a parametric vector equation of parameter t.)

I realize this works because T(t) is orthogonal to T'(t), but I don't understand why the derivative of the vector T is orthogonal to T itself.

Can anyone explain to me why the derivative of a tangent vector is orthogonal to the tangent vector? Thanks.
 
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lordkelvin said:
Can anyone explain to me why the derivative of a tangent vector is orthogonal to the tangent vector? Thanks.

In general it is not true but if the tangent vectors have constant length then the derivative of the length is zero.
 

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