Concentration of minority carriers in a pn junction

[jeffy]

Homework Statement

A semiconductor p-n junction is fabricated where the doping concentration on the p and n sides of the junction is Na=1E18cm^-3 and Nd=1E16cm^-3 respectively. Given that ni=1.18E10cm^-3, T=300k calculate:

a) The majority and minority carrier concentrations in the neutral bulk regions on either side of the junction.

Homework Equations

ni^2=(npo)(Na) and ni^2=(Pno)Nd
where npo is the concentration of electrons in the p doped region and pno is the concentration of holes in the n region

The Attempt at a Solution

using the above equations i got npo=139.24 cm^-3 and 13924cm^-3 for the minority concentrations. I want to ask if i did this right because i think these concentrations are kinda low


thanks for reading

 

[MATLABdude]

Have more confidence in yourself! Plugging the equation into Google verifies your calculations:
http://www.google.ca/search?q=(1.18E10cm^-3)^2/(1E18cm^-3) to cm^-3

 

[jeffy]

ya but is the set up correct, because 139.24cm^-3 is low comaring to 1.18E18cm^-3, but then again they are minority carriers