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Conceptual double integral question

  1. Nov 4, 2012 #1
    1. The problem statement, all variables and given/known data

    ∫∫x2sin(y2)dA; R is the region that is bounded by y=x3
    y=-x3, and y=8.

    While working out the regions for this integral I set the inner integral to -y1/3 to y1/3. and the outer integral from 0 to 8. The book however set the inner integral from 0 to y1/3. However we both got the same answer, is there a reason for this?



    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Nov 4, 2012 #2


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    Hi Mdhiggenz! :smile:
    Either one of you made a mistake, or the book multiplied by 2 after integrating. :confused:
  4. Nov 4, 2012 #3
    Hey Tim,

    Yea the books answer is quite strange, the way I reasoned my answer is when I drew the graph R2: goes from -y^1/3 to positive y^1/3. Unless the book chose not to include the negative region.

  5. Nov 4, 2012 #4


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    Your method looks fine. :confused:
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