Conditional Distribution of Multinomial Random Variables

Click For Summary
SUMMARY

The discussion focuses on the conditional distribution of a multinomial random variable vector Y = (Y_1, Y_2, ..., Y_k) with parameters n and π = (π_1, π_2, ..., π_k). It establishes that the conditional distribution of Y_1 given Y_1 + Y_2 = m is binomial with parameters n = m and π = π_1 / (π_1 + π_2). The participants explore the application of conditional probability definitions and note that while this holds for Poisson distributions, the challenge lies in proving it for multinomial distributions.

PREREQUISITES
  • Understanding of multinomial distributions and their properties
  • Knowledge of conditional probability and its applications
  • Familiarity with binomial distributions and their parameters
  • Basic concepts of random variables and probability theory
NEXT STEPS
  • Study the derivation of conditional distributions in multinomial settings
  • Learn about the relationship between Poisson and multinomial distributions
  • Explore applications of conditional probability in statistical modeling
  • Investigate advanced topics in probability theory, such as the Law of Total Probability
USEFUL FOR

Statisticians, data scientists, and students of probability theory who are looking to deepen their understanding of conditional distributions and their applications in multinomial contexts.

broegger
Messages
257
Reaction score
0
I've been staring at this for hours. Any hints?

Let the vector [tex]Y = (Y_1,Y_2,\dots,Y_k)[/tex] have a multinomial distribution with parameters n and [tex]\pi = (\pi_1,\pi_2,\dots,\pi_k)[/tex]:

[tex]\sum_{i=1}^{k}Y_i = n, \quad \sum_{i=1}^{k}\pi_i = 1[/tex]​

Show that the conditional distribution of [tex]Y_1[/tex] given [tex]Y_1+Y_2=m[/tex] is binomial with n = m and [tex]\pi = \frac{\pi_1}{\pi_1+\pi_2}[/tex].

I've tried to apply the definition of a conditional probability and sum over the relevant events in the multinomial distribution, but it gives me nothing.

Thanks.
 
Physics news on Phys.org
Hmmm, this works if they are Poisson. Not sure if it works if it is multinomial. The standard way to do this would be to compute P[X_1=x|X_1+Y_2=m], as you tried.

Edit: I should be more precise. If Y_1 and Y_2 poisson r.v. with paramaters lambda1 and lambda2, then Y_1 | Y_1+Y_2=m is distributed as Binomial(m, lambda1/(lambda1+lambda2)).
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K