(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A standard deck of 52 cards of 4 suits, each with 13 denominations, is well shuffled and dealt out to four players, N, S, E and W, who each receive 13 cards. If N and S have exactly ten cards of a specified suit between them, show that the probability that three remaining cards of the suit are in one player's hand (either E or W) is 0.22

2. Relevant equations

[itex]P(A | B) = \frac{P(A \cap B)}{P(B)}[/itex]

3. The attempt at a solution

I completed this question a few months ago with the solution:

[itex]\frac{2\binom{23}{10}}{\binom{26}{13}\binom{13}{13}} = 0.22[/itex]

Problem is, I have no idea how I got to that solution. I try now but end up with probabilities greater than 1, or very very small probabilities. Some clarification on how I got my solution, or how anyone would solve this, would be appreciated :)

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# Homework Help: Conditional Probability and Drawing Cards

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