Conducting sphere surrounded by insulator with dielectric constant

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SUMMARY

The discussion focuses on a conducting sphere of radius A with a charge +Q, surrounded by an insulating material with a dielectric constant defined as εr = 2exp[-(r/a-1)]². The values of electric displacement field (D), electric field (E), polarization (P), and charge density (ρ) are derived using Gauss's Law. For regions outside the sphere, D is expressed as D = q/4πr² and E as E = q/4πε₀r². Inside the sphere, both D and E are zero.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with dielectric materials and their properties
  • Knowledge of electric displacement field (D) and electric field (E) concepts
  • Basic calculus for evaluating exponential functions
NEXT STEPS
  • Study the application of Gauss's Law in different geometries
  • Explore the behavior of electric fields in dielectric materials
  • Learn about the relationship between electric displacement (D), electric field (E), and polarization (P)
  • Investigate the effects of varying dielectric constants on electric fields
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Students and professionals in electrical engineering, physicists, and anyone studying electrostatics and dielectric materials.

zhillyz
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Homework Statement



A conducting sphere of radius A has a charge +Q on it and is surrounded by an insulating material whose dielectric constant varies with radius according to εr = 2exp[-(r/a-1)]2. The dielectric has a spherical outer boundary B. Find the values of D, E, P, ρ as a function of r.

Homework Equations



εr = 2exp[-(r/a-1)]2,

Gauss's Law?

The Attempt at a Solution



Outside conducting sphere:

D directed radially outward so using symmetrical surface integral form of Gauss law, D = q/4∏r2.

E=D/ε0 = q/4∏ε0r2.

Inside sphere:
D=0, E=0.

Not sure if this is right or what next steps to take?
 
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zhillyz said:

Homework Statement



A conducting sphere of radius A has a charge +Q on it and is surrounded by an insulating material whose dielectric constant varies with radius according to εr = 2exp[-(r/a-1)]2. The dielectric has a spherical outer boundary B. Find the values of D, E, P, ρ as a function of r.

Homework Equations



εr = 2exp[-(r/a-1)]2,

Gauss's Law?

The Attempt at a Solution



Outside conducting sphere:

D directed radially outward so using symmetrical surface integral form of Gauss law, D = q/4∏r2.

E=D/ε0 = q/4∏ε0r2.

Inside sphere:
D=0, E=0.

Not sure if this is right or what next steps to take?
Hello zhillyz. Welcome to PF!

I take it that the spherical shell has inner radius A, and outer radius, B.

E = D/ε0 outside the dielectric shell; where r > B .

For A < r < B, E = D/εr .
 

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