Conduction to Displacement Current Ratio

[atomicpedals]

Homework Statement

For copper we find that J=$$\sigma$$E , where $$\sigma$$ has the value 5.8x10^7 mksc units. If an alternating electric field represented by E₀e^i$$\omega$$t exists within the copper. Find the ratio of the conduction to the displacement current density at a frequency of 1megacycle/sec.

Homework Equations

J=$$\sigma$$ dE₀/dt

The Attempt at a Solution

So I'm hoping this is a straight forward as I'm making it out to be, minus my own issues with the units. I think it follows like this, but it seems too easy!

Please excuse my tex failures below...

J=$$\sigma$$ dE₀/dt = i$$\omega$$$$\sigma$$E₀
$$\omega$$$$\sigma$$E₀=E₀/J = 1.04x10^12

 

[atomicpedals]

Got it, I think, J_c/J_d = $$\sigma$$ / $$\omega$$ $$\epsilon$$