1. The problem statement, all variables and given/known data A capacitor is made of two parallel plates of area A, separation d. It is being charged by an AC source. Show that the displacement current inside the capacitor is the same as the conduction current. 2. Relevant equations Idisp = ε(dΦE/dt) Q = CV C = Aε/d Xc = 1/(2πƒC) Q(t) CV(1-e-t/τ) 3. The attempt at a solution First of all, as it's an AC circuit so we won't be completely charging the capacitor, so I don't think we will use the exponential charging equation for a capacitor. The displacement current can be obtained by differentiating Q=CV. That gives (dQ/dt) = C(dV/dt). Assuming V = Vosin(2πft), we get a suitable expression for Id. This leads to a current answer. But of we want to use the electric flux equation then how can we do that?