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- Thread starter Ananya0107
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"When ellipse and hyperbola are confocal, then they are orthogonal curves"

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actually I was thinking too much .... Eccentricity of the hyperbola = 5/3 from the question , and it passes through (±3, 0) , its equation therefore is x^2/9 - y^2/b^2 =1 where 1+ b^2/9 = 25/9 therefore equation of hyperbola is x^2/9 - y^2/9 = 1 and its focii are ±5,0

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True..

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