Confused about equation solving

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Discussion Overview

The discussion revolves around the process of solving an equation related to physics, specifically involving kinetic and potential energy. Participants express confusion about the manipulation of the equation, particularly regarding the factor of "2" in the context of solving for velocity.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the origin of the factor "2" in the equation after multiplying by ½.
  • Another participant clarifies that the correct operation is to multiply both sides of the equation by 2, maintaining the equality.
  • There is a humorous analogy about cutting an apple to illustrate confusion over fractions, which leads to a correction about the multiplication of fractions.
  • A later reply emphasizes the importance of using parentheses in the equation to clarify the terms being square-rooted.
  • It is noted that mathematically, there are two potential solutions for the variable v1, indicated by the ± sign.

Areas of Agreement / Disagreement

Participants express confusion and seek clarification, indicating that there is no consensus on the understanding of the equation manipulation. Multiple viewpoints and interpretations of the equation remain present.

Contextual Notes

Some participants highlight the need for clarity in mathematical notation, particularly regarding the use of parentheses, which may affect the interpretation of the equation. The discussion also reflects uncertainty about the implications of the factor "2" and how it relates to the overall equation.

JesseK
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Hey!

I'm confused about this:

½v21 = ½v20 - gh1

v21 = v20 - 2gh1

v1 = √v02 - 2gh1

Soo, what basically happened here when solving the equation for v1? I understand that the equation should be multiplied by ½ and then take a square root in order to solve for v1, but what's that factor "2" before gh (bold text). Where did that come from?

Thank you!
 
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JesseK said:
I understand that the equation should be multiplied by ½
No, you are multiplying by 2. Does that answer your question?
 
As @Ibix says, multiply both sides of the equation by 2 (so the equal sign still holds -- always do the same operation on both sides of the equation when simplifying it):

2(\frac{1}{2}v_1^2) = 2(\frac{1}{2}v_0^2 - gh_1)
 
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JesseK said:
1/2 * 1/2 = 1
What? If I have an apple and I cut it in half, and cut one if the halves in half, you expect the half of a half to be a whole apple?
 
Ibix said:
What? If I have an apple and I cut it in half, and cut one if the halves in half, you expect the half of a half to be a whole apple?

Yeah, it was my bad, sorry. Obviously 1/2 * 1/2 = 1/4 haha :D
 
berkeman said:
As @Ibix says, multiply both sides of the equation by 2 (so the equal sign still holds -- always do the same operation on both sides of the equation when simplifying it):

2(\frac{1}{2}v_1^2) = 2(\frac{1}{2}v_0^2 - gh_1)

Oh, so every term on both sides of the equation should be multiplied by 2 (those brackets)? Now, I gotcha, thank youu! :D
 
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JesseK said:
Hey!

I'm confused about this:

½v21 = ½v20 - gh1

v21 = v20 - 2gh1

v1 = √v02 - 2gh1
The line above confused me, at first, since it looks like you're taking the square root only of the ##v_0^2## term. You really should be using parentheses, like this: v1 = √(v02 - 2gh1)

Also, mathematically speaking, there will be two solutions for ##v_1##:
v1 = ±√(v02 - 2gh1)
JesseK said:
Soo, what basically happened here when solving the equation for v1? I understand that the equation should be multiplied by ½ and then take a square root in order to solve for v1, but what's that factor "2" before gh (bold text). Where did that come from?

Thank you!
 

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