- #1

- 19

- 1

I'm confused about this:

½v

^{2}

_{1}= ½v

^{2}

_{0}- gh

_{1}

v

^{2}

_{1}= v

^{2}

_{0}-

**2gh**

_{1}v

_{1}= √v

_{0}

^{2}- 2gh

_{1}

Soo, what basically happened here when solving the equation for v1? I understand that the equation should be multiplied by ½ and then take a square root in order to solve for v1, but what's that factor "2" before gh (bold text). Where did that come from?

Thank you!