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• JesseK
The equation should be multiplied by ½, but in order to solve for v1, you need to take a square root. That factor "2" before gh (bold text) is just telling you to take the square root of √(v02 - 2gh1).f

#### JesseK

Hey!

½v21 = ½v20 - gh1

v21 = v20 - 2gh1

v1 = √v02 - 2gh1

Soo, what basically happened here when solving the equation for v1? I understand that the equation should be multiplied by ½ and then take a square root in order to solve for v1, but what's that factor "2" before gh (bold text). Where did that come from?

Thank you!

I understand that the equation should be multiplied by ½

As @Ibix says, multiply both sides of the equation by 2 (so the equal sign still holds -- always do the same operation on both sides of the equation when simplifying it):

$$2(\frac{1}{2}v_1^2) = 2(\frac{1}{2}v_0^2 - gh_1)$$

JesseK
1/2 * 1/2 = 1
What? If I have an apple and I cut it in half, and cut one if the halves in half, you expect the half of a half to be a whole apple?

What? If I have an apple and I cut it in half, and cut one if the halves in half, you expect the half of a half to be a whole apple?

Yeah, it was my bad, sorry. Obviously 1/2 * 1/2 = 1/4 haha :D

As @Ibix says, multiply both sides of the equation by 2 (so the equal sign still holds -- always do the same operation on both sides of the equation when simplifying it):

$$2(\frac{1}{2}v_1^2) = 2(\frac{1}{2}v_0^2 - gh_1)$$

Oh, so every term on both sides of the equation should be multiplied by 2 (those brackets)? Now, I gotcha, thank youu! :D

berkeman
Hey!

½v21 = ½v20 - gh1

v21 = v20 - 2gh1

v1 = √v02 - 2gh1
The line above confused me, at first, since it looks like you're taking the square root only of the ##v_0^2## term. You really should be using parentheses, like this: v1 = √(v02 - 2gh1)

Also, mathematically speaking, there will be two solutions for ##v_1##:
v1 = ±√(v02 - 2gh1)
JesseK said:
Soo, what basically happened here when solving the equation for v1? I understand that the equation should be multiplied by ½ and then take a square root in order to solve for v1, but what's that factor "2" before gh (bold text). Where did that come from?

Thank you!