warfreak131 said:
I have taken modern and quantum physics, and I am familiar with wave functions, but the functions we worked with only dealt with the probability of it being at a certain point R away from the nucleus, or it's expectation value, not the radius of the electron itself.
Sure. Because, so far as we are able to tell, an electron does not have any internal structure. As ModusPwnd said, it's elementary. That is, it does not have any internal "working parts." We don't actually have a measured size, just upper limits. Those limits are getting pretty small.
A proton is "made up" of three quarks and some gluons. These spend their time some distance apart on average. So a proton behaves like a blob of stuff with a (very small) finite size. It scatters other particles very differently from how it would if it were zero size. It shows three scattering centres. The quarks are, so far as we can tell, elementary. They have not, as yet, shown any internal structure.
The definition of the size of a proton is kind of complicated. You can look at things like the distance the quarks appear to be under scattering by different energy or type of particles. Such as when you scatter them off other protons. Or off anti-protons. Or off electrons or positrons. Or when you scatter alpha particles off of them. You can also use the size as estimated based on various calculations from various phenomenological (or semi-phenomenological) models. (It's pretty cool that the spell checker here had no problem with that term.) For example, there has been a lot of work done on things like the bag model of protons. You can also get an estimate from things like nuclear interactions and stacking in things like larger atomic nuclei. You can estimate the size of a uranium nucleus (say U-238) from scattering, and then say that a proton is 1/238th of that size. There are semi-phenomenological models for nuclei such as the liquid drop model. And there are some results from numerical schemes like lattice gauge calculations.
Another method is by studying the energy levels of atoms. Because the proton, and the neutron, have finite size, the electric charge distribution of the nucleus is not point-like. That produces a minor perturbation on the energy levels of electrons in an atom. By measuring these perturbations we can get some idea of the size of a nucleus. That was a keen 4th year homework assignment that wound up requiring a lot of pages of algebra.
And each of these methods gives a bit different answer.
Dan