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Homework Statement
Find the formula
Σ[n, i =1](2i - 1) = 1+3+5+...+(2n-1)
Homework Equations
The Attempt at a Solution
When I look at the back of the book , I got this solution which is
1, Sigma(2i - 1) = 1+3+5+...+(2n-1)
2, = 1+2+3+...+2n-2(1+..+n)
3, = ((2n)(2n+1)) /2 - n(n+1)
4, n^2
What i don't get is what happened from step 1 to 2 and 2 to 3?
It seems that there are hidden steps there that were not written down and therefore and I am really confused about this solution.
Thank you guys very much.