Confused on amperes in primary & secondary circuits

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SUMMARY

The transformer in question has 500 turns in the primary coil and 4000 turns in the secondary coil. The secondary voltage is calculated to be 880V when the primary voltage is 110V, using the formula V2/V1 = N2/N1. For the current calculations, when 5 amperes flow through the secondary, the primary current is determined to be 40 amperes, and when 8 amperes flow through the secondary, the primary current is 64 amperes, applying the formula Ip/Is = Ns/Np.

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Homework Statement



A transformer has 500 turns in its primary coil and 4000 turns in its secondary. (a) What will be the voltage in the secondary if the primary voltage is 110? (b) If 5 amperes flow through the secondary circuit of the transformer, what will the current in the primary be? (c) If there are 8 amperes in the secondary, how many are there in the primary?

I'm a little confused on whether I'm inverting the equation correctly on parts b and c - can someone let me know if this is the formula they use?

Homework Equations





The Attempt at a Solution



v2/v1=n2/n1 So V2/110=4000/500 = 880V

b.)Ip/Is=Ns/Np = Ip/5 = 4000/500 = 40 A

c.)Ip/Is=Ns/Np = Ip/8 = 4000/500 = 64 A
 
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kriegera said:

Homework Statement



A transformer has 500 turns in its primary coil and 4000 turns in its secondary. (a) What will be the voltage in the secondary if the primary voltage is 110? (b) If 5 amperes flow through the secondary circuit of the transformer, what will the current in the primary be? (c) If there are 8 amperes in the secondary, how many are there in the primary?

I'm a little confused on whether I'm inverting the equation correctly on parts b and c - can someone let me know if this is the formula they use?

Homework Equations





The Attempt at a Solution



v2/v1=n2/n1 So V2/110=4000/500 = 880V

b.)Ip/Is=Ns/Np = Ip/5 = 4000/500 = 40 A

c.)Ip/Is=Ns/Np = Ip/8 = 4000/500 = 64 A

Looks correct to me.
 

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