Confusing Old time Measurements =(

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Homework Help Overview

The problem involves converting the speed of light into megafurlongs per fortnight, utilizing historical units of measurement such as furlongs and fortnights. The context is rooted in unit conversion and dimensional analysis within the realm of physics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion of speed from miles per hour to furlongs per fortnight, questioning the setup of the conversion factors. Some suggest breaking the problem into smaller steps to facilitate understanding.

Discussion Status

Guidance has been offered regarding the initial setup of the conversion, with some participants providing partial expressions to assist in the calculations. There is acknowledgment of a correction regarding the speed of light, indicating an ongoing exploration of the problem.

Contextual Notes

There is a noted confusion regarding the units of speed, particularly the distinction between miles per second and miles per hour, as well as the implications of converting to larger units like furlongs and fortnights.

Teenytiny1991
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Homework Statement


A furlong is and old British unit of length equal to 0.125 mi, derived from the length of a furrow in an acre of plowed land. A fortnight is a unit of time corresponding to two weeks, or 14 days and nights. Find the speed of light in megafurlongs per fortnight. (one megafurlong equals a million furlongs).


Homework Equations



speed= distance/time
fur=0,125 mi
for=2 weeks
mg= 1,000,000 fur

The Attempt at a Solution



1 mf/ 1,000,000 fur x 1 fur/0.125 mi x 0.125 mi/ 1fur x 2w/1 for = ... I'm stumped here. i can't understand which way to set it up so that i am only left with mf/for
 
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If you are inexperienced with this, I suggest that you do it in steps instead of trying all at once. I will get you started, but you will have to finish.

You start with what you know. The speed of light is c = 186,000 mile/hr. So you write

c=186,000\frac{mile}{hr}

Now you are given that

1 mile=\frac{1}{0.125}fu

Put that in the previous expression to get

c=186,000\frac{1}{0.125}\frac{fu}{hr}

Now

1fu=10^{-6} Mfu

Put that in the expression to get

c=\frac{186,000\times10^{-6}}{0.125}\frac{Mfu}{hr}

Finish the question by proceeding along these lines to get the fortnight in the denominator. Incidentally, you don't really need the 186,000 there. You could as well start with 1 mile/hr to get the conversion factor then multiply the result by 186,000.*** Correction ***

As pointed out by mgb_phys, the speed of light is 186,000 miles/sec. So the conversion is from "sec" to "fortnight". My apologies for the confusion.
 
Last edited:
The speed of light in SI units is defined as (approximately) 3 \times 10^8 m/s.
How many miles per second is this?
So how many furlongs per second?
 
First you need to estimate the answer so you know if you got it right.
A furlong is less than a mile so a speed in furlongs/hour would be a larger number than mi/hour (ie at the same speed you do more furlongs than you do miles) - just like a speed in km/h is a bigger number than in mph.
But a fortnigth is much bigger than an hour so at the same speed you would cover a much bigger distance. So the same speed would be a much bigger number in f/f

Converting is just a matter of fractions.

Assuming you start in miles/sec (c = 186,000 mi/s)
furlongs / fortnight = miles/second * ( fortnight/second) / ( furlongs / mile )

furlongs/mile = 0.125, fortnight/second = 14*24*3600
So 186,000 * (14*24*3600/0.125) =
 
kuruman - slight typo, it's 186,000 mi/SECOND

Teenytiny1991 - using Furlong/Fortnight/Firkin is to teach how to do these sort of conversion. It's just a bit more fun than doing mi/s to m/s or J to eV.
 

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