Confusion about definition of a splitting field

Click For Summary
SUMMARY

The discussion centers on the definition of a splitting field in the context of Galois theory, specifically regarding the polynomial ##f(x)## over a field ##F##. The exercise states that if ##f(x)## is an irreducible polynomial of degree ##n## and ##E/F## is its splitting field, then ##n## divides ##[E:F]##. The confusion arises when considering separable polynomials, where the user questions the relationship between the degree of the polynomial and the order of the Galois group ##Gal(E/F)##. The conclusion drawn is that the polynomial ##(x^2+1)^2## is not irreducible and thus not separable, which resolves the user's concern about the divisibility of degrees.

PREREQUISITES
  • Understanding of Galois theory concepts, particularly splitting fields.
  • Familiarity with irreducible and separable polynomials.
  • Knowledge of Galois groups and their properties.
  • Basic proficiency in polynomial algebra and field theory.
NEXT STEPS
  • Study the properties of splitting fields in Galois theory.
  • Learn about irreducible and separable polynomials in detail.
  • Investigate the relationship between polynomial degrees and Galois group orders.
  • Review induction techniques in the context of polynomial factorization.
USEFUL FOR

Mathematicians, students of abstract algebra, and anyone studying Galois theory who seeks clarity on the concepts of splitting fields and polynomial separability.

issam el mariami
Thread moved from the technical forums to the schoolwork forums.
TL;DR Summary: Confision about definition of a splitting field

I have an exercise that tells me to show that if ##F##is a field and ##f(x)## is a polynomial over F which irreducible of degree n and ##E/F## is a splitting field of ##f(x)## then n divides ##[E:F]##, DONE!

The second part is what bothers me, it says: now suppose ##f(x)## is separable, show that n divides the order of ##Gal(E/F)##. See exercise 78, J Rotman - Galois Theory (Universitext), second edition. Now from the theorem 56 (of the same book) I can tell that ##|Gal(E/F)|=[E:F]##, nice!!!.

Now, for sure I need to apply part one of the exercise, so here how it goes: from the definition of a separable polynomial we know that (stik right now for just the case of two factors, because the general case cane be done by induction) ##f(x)= a f_1(x) f_2(x)## where a is an element of F and the two foregoing polynomials are irreducible (NOT NECESSARILY DISTINCT) and EACH one of them has no repeated roots.

But, then It cames to my mind that ##|\mathbb{C}: \mathbb{R}|=2##, and ##(x^2+1)(x^2+1)## is separable over ##\mathbb{R}## with degree four, But ##x^2+1## (itself!) is separable so by the same theorem ##|Gal(\mathbb{C}:\mathbb{R})|=2## But four does not divide two. Could someone please tell me where I messed up, and if I'm right about using induction to resolve the problem (so ##deg(f_1(x))deg(f_2(x))=deg(f(x)##) divides ##[E:F]##).

[LaTeX edited by a Mentor]
 
Last edited by a moderator:
Physics news on Phys.org
##(x^2+1)^2## isn't irreducible and therefore not separable.
 

Similar threads

Replies
6
Views
2K
  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K