Confusion About Oscillating Mass

Click For Summary
SUMMARY

The discussion centers on the dynamics of an oscillating mass attached to a crankshaft in a frictionless environment. Participants clarify that in a Hamiltonian system with one degree of freedom, the mass will oscillate periodically even when external torque is removed, provided there is no energy loss. The conversation highlights the necessity of a flywheel for sustained motion and the implications of mass distribution on oscillation frequency. Key equations discussed include torque calculations represented as τ = Mω²l², emphasizing the importance of mass in maintaining oscillation.

PREREQUISITES
  • Understanding of Hamiltonian mechanics and periodic motion
  • Familiarity with torque and angular velocity concepts
  • Basic knowledge of energy conservation principles in mechanical systems
  • Experience with mathematical modeling of physical systems
NEXT STEPS
  • Explore the principles of Hamiltonian mechanics in detail
  • Study the role of flywheels in mechanical systems for energy storage
  • Learn about the effects of mass distribution on oscillation frequency
  • Investigate real-world applications of oscillating systems in engineering
USEFUL FOR

Students of physics, mechanical engineers, and anyone interested in the dynamics of oscillating systems and energy conservation principles in mechanics.

person123
Messages
326
Reaction score
52
I'm sure there's an obvious answer to this, but this problem has been confusing me for some time.

Imagine there were a massive object attached to the end of a crankshaft. A force is applied to accelerate the crankshaft, causing the mass to oscillate. Assuming there is no friction, what would happen to the system when the force is no longer applied? It shouldn't be possible for it to slow down if there's no energy loss, but wouldn't it require a force to continue to accelerate the mass back and forth?
 
Last edited:
Physics news on Phys.org
picture is needed
 
zwierz said:
picture is needed
I'm not exactly sure what you're looking for, but this is the basic idea.

crankshaft.png
 
the system will oscillate This is a Hamiltonian system with one degree of freedom
 
And it will continue to oscillate at the same rate even when the torque is no longer applied?
 
What does the "rate" mean? This will be nonlinear oscillation. Is gravity applied?
 
I mean the frequency of the oscillation of the mass. I don't understand what you're asking.
 
The motion of the system will be periodic
 
One thing to think about that may not have occurred to you - whatever your axle is attached to will also wobble so that the centre of mass does not move. This is analogous to the Earth-Moon system, which revolves around a point (the barycentre) slightly offset ftom the centre of the Earth.

Does that help?
 
  • Like
Likes   Reactions: person123
  • #10
zwierz said:
Is gravity applied?
I should have mentioned that. It would make sense not to include gravity just for the purpose of simplifying things, I suppose.
 
  • #11
Ibix said:
whatever your axle is attached to will also wobble so that the centre of mass does not move
that is wrong
person123 said:
I should have mentioned that. It would make sense not to include gravity just for the purpose of simplifying things, I suppose.
ok anyway the motion will be periodic
 
  • #12
zwierz said:
that is wrong
How is momentum conserved if the centre of mass moves?
 
  • #13
Ibix said:
ow is momentum conserved if the centre of mass moves?
who does say that momentum conserved?
 
  • #14
zwierz said:
who does say that momentum conserved?
How can momentum not be conserved? I assume that even if the mechanism were fixed on the earth, it would cause the Earth to oscillate very slightly in response (as ibix described).
 
  • Like
Likes   Reactions: Ibix
  • #15
person123 said:
How can momentum not be conserved. I assume that even if the mechanism were fixed on the earth, it would cause the Earth to oscillate very slightly in response (as ibix described).
Oh if you include the Earth in the system then I withdraw my objections :)
 
  • #16
Ibix said:
One thing to think about that may not have occurred to you - whatever your axle is attached to will also wobble so that the centre of mass does not move. This is analogous to the Earth-Moon system, which revolves around a point (the barycentre) slightly offset ftom the centre of the Earth.

Does that help?

I think that makes sense, but I still have one more question which relates to the initial purpose of this thread.
I was trying to calculate the torque required to oscillate the mass at a constant frequency. So I found the velocity of the mass, and I then found the derivative, which gave me the acceleration. This allowed me to find the torque at the point in which the velocity of the mass was zero and the acceleration was at its maximum. (It gave me τ=Mω^2l^2, in which l is the length of the short rod). However, it doesn't seem to make sense to calculate this when there isn't any torque required to maintain that constant oscillation. I can't seem to reconcile this confusion with the explanation.
 
Last edited:
  • #17
person123 said:
I think that makes sense, but I still have one more question which relates to the initial purpose of this thread.
I was trying to calculate the torque required to oscillate the mass at a constant frequency. So I found the velocity of the mass, and I then found the derivative, which gave me the acceleration. This allowed me to find the torque at the point in which the velocity of the mass was zero and the acceleration was at its maximum. (It gave me τ=Mω^2l^2, in which l is the length of the short rod). However, it doesn't seem to make sense to calculate this when there isn't any torque required to maintain that constant oscillation. I can't seem to reconcile this confusion with explanation.
Are you assuming that all parts, except the block are masses? In that case the total energy is zero when the block is at rest, so the oscillation won't be maintained without an applied torque.
 
  • #18
A.T. said:
Are you assuming that all parts, except the block are masses? In that case the total energy is zero when the block is at rest, so the oscillation won't be maintained without an applied torque.
Yes, I'm assuming all other parts are without mass. Isn't that contradictory to ibix's argument, or is this just a misunderstanding on my part?

However, let's say the mass of the other parts were just extremely small. Would the frequency of oscillation decrease or remain constant over time?

Also, how can there be no energy in the system if it was initially in motion and no energy was lost?
 
  • #19
person123 said:
Also, how can there be no energy in the system if it was initially in motion and no energy was lost?
Your assumptions are obviously contradictory then.

person123 said:
However, let's say the mass of the other parts were just extremely small. Would the frequency of oscillation decrease or remain constant over time?
Without energy dissipation, constant.
 
  • #20
A.T. said:
Without energy dissipation constant.

But can't you approximate what would occur in the system by considering the other parts without mass if the mass of those parts are in reality very small?
 
  • #21
person123 said:
But can't you approximate what would occur in the system by considering the other parts without mass if the mass of those parts are in reality very small?
You have already answered this question, by pointing out the contradiction it leads to. How are massless rigid parts supposed to store energy, in order to conserve it, while the block stops at each turnaround?
 
  • #22
The problem is that if nothing except the mass has mass then any forces applied cause infinite acceleration. You can certainly consider your crankshaft to be massless, but it has to be attached to something with mass in order for it to have been able to produce a torque in the first place without itself instantly spinning up to infinite speed.
 
  • #23
I haven't quite locked on to what the problem is but let's try a few things :

The configuration is like that of a normal I/c engine . Crankshaft , connecting rod and notionally a piston . The piston has a large mass but the other components are massless . Conventional arrangements of bearings etc. but with zero friction .

If the crankshaft is initially rotated at constant rpm by an external power source then the piston will move back and forth in a straight line . Motion will be something like SHM but with some higher order motion components added .

When the external power source is disconnected the piston will continue to move until it reaches an extremity of it's travel where it will stop .

To make the motion continue beyond that stop point there needs to be a heavy flywheel fitted to the crankshaft .
 
  • #24
I asked what would happen to the frequency of oscillation if the mass of the rods were extremely small.
A.T. said:
Without energy dissipation, constant.

Nidum said:
To make the motion continue beyond that stop point there needs to be a heavy flywheel fitted to the crankshaft .
According to A.T., ignoring friction, wouldn't any mass cause the oscillation to be maintained at a constant frequency?
 
  • #25
I don't see any contradiction between what AT has said and what I have said .

When the external drive is disconnected the piston will just continue in motion until it can go no further . There is then no torque on the crankshaft to make it rotate and no force on the piston to start it moving again .

To make the motion keep going there needs to be enough residual rotational KE in the crankshaft to carry it past dead centre and then generate enough torque to produce a force in the connecting rod sufficient to start the piston moving again .

Zero mass crankshaft components can't store any KE at all .

In a real situation the crankshaft components themselves could be made sufficiently massive to store enough KE but more commonly the crankshaft components are kept relatively light and a massive flywheel is fitted instead .
 
  • #26
All right. So here's my understanding of how it would work.

If the mass of the flywheel were extremely large and the oscillating mass extremely small, the angular velocity of the flywheel would be almost constant. As the former decreases and the latter increases, the angular velocity would fluctuate to a greater extent.

If the system were connected to the earth, it would cause the Earth to oscillate (extremely slightly).

If the mass of the rods and flywheel were nonexistent, when the velocity of the oscillating mass reaches zero it would remain still because there is no stored kinetic energy.

If there were no friction in the system and the connecting rods had any mass at all, it would oscillate perpetually.

Is this the right idea?
 
Last edited:
  • #27
person123 said:
If the system were connected to the earth, energy would be conserved because the oscillating mass would pull on the earth, causing it to accelerate.
No, it doesn't work like that. In the rest frame of the total center of mass (Earth and block), there is a time point when both masses are at rest, so total KE is zero. This is obviously inconsistent with the other assumptions (etc. total rigidity) which preclude energy dissipation.
 
  • #28
A.T. said:
No, it doesn't work like that. In the rest frame of the total center of mass (Earth and block), there is a time point when both masses are at rest, so total KE is zero. This is obviously inconsistent with the other assumptions (etc. total rigidity) which preclude energy dissipation.
OK. I think I get that—I'll edit my previous post. I'm assuming this inconsistency is because energy conservation would require completely elastic collisions which wouldn't happen if the parts were perfectly rigid.
 
  • #29
person123 said:
If there were no friction in the system and the connecting rods had any mass at all, it would oscillate perpetually.

Is this the right idea?

Not quite . There is a minimum value of energy storage capacity needed in the flywheel / crank / con rod assembly to ensure continuous motion .

Please note that trying to explain exactly how a theoretical system that can't actually exist works is difficult and often misleading . You would be better off from this point on in this discussion if you drew up a realistic system which we could then analyse more definitively . When you see how the energy in a real system transfers between components you should be able to understand all of this problem much more easily .

Anyway if you want to continue we need to develop a proper mathematical model of this type of system .
 
Last edited:
  • #30
All right. I think the problems I'm used to dealing with are simple enough that I never have to deal with the inconsistencies of these theoretical cases (I'm only in high school taking regents physics).

Should I provide specific values for the mass of the rods (and possibly the friction) or should I just assume they're low but not nonexistent?

If I assume that they are low, would my equation τ=mω^2l^2 (which didn't take into account the mass of the rods) still be a good approximation.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
17
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K