Confusion about the Energy Density of EM waves

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SUMMARY

The energy density of electromagnetic (EM) waves is calculated using the electric field (E) and magnetic field (B) components. The total energy density formula is given by $$u = \frac {\epsilon_0E^2}{2} + \frac {B^2}{2 \mu_0}$$. For instantaneous energy density, the peak values of E and B, denoted as E0 and B0, are used, while for average energy density, the values are adjusted to E = E0 / √2 and B = B0 / √2. Different references may discuss either instantaneous or average energy density, necessitating careful reading to discern the context.

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PumpkinCougar95
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I am a bit confused about the energy density in an EM wave. why do we take the Peak value of E vector while calculating the energy density?

Like if the E field is ##E_0 Sin(kx-wt)## what is the energy density of the EM wave(Magnetic + Electric)?

is it A) ##\frac {e_0E_0^2}{2} ## or B) ## e_0E_0^2 ## ?

in the A) part I have used the Average value of E field as ## <E^2> ~ = \frac {E_0^2 }{2}##
 
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PumpkinCougar95 said:
I am a bit confused about the energy density in an EM wave.
PumpkinCougar95 said:
I have used the Average value of E field as ## <E^2> ~ = \frac {E_0^2 }{2}##
Is the electric field the only field in an electromagnetic wave?
 
No, There is the B field too.

so the total Energy density is:
$$u = \frac {\epsilon_0E^2}{2} + \frac {B^2}{2 \mu_0}$$
My question is do we take ##E=E_0## and ##B=B_0## while calculating? Or do we Use ##E= \frac {E_0}{ sqrt{2} }## and ##B=\frac {B_0}{sqrt{2}}## ? Because in multiple books i have seen ##E=E_0## and ##B=B_0## which doesn't make any sense to me.
 
Are you looking for the "instantaneous" energy density at a point in space and time in the wave, or the average energy density over a volume of space or period of time? Your equation for ##u## is the "instantaneous" energy density at any point in the wave, using the values of ##E## and ##B## at that point. Setting ##E = E_0## and ##B = B_0## gives you the maximum energy density, ##u_0##, at the maxima of the waves. Setting ##E = E_0 / \sqrt 2## and ##B = B_0 / \sqrt 2## gives you the average energy density, ##\langle u \rangle##, for a sinusoidal wave.

More carefully, $$\langle u \rangle = \frac 1 2 \varepsilon_0 \langle E^2 \rangle + \frac 1 {2 \mu_0} \langle B^2 \rangle = \frac 1 4 \varepsilon_0 E_0^2 + \frac 1 {4 \mu_0} B_0^2$$

Most books take one more step, using the relationship between ##E## and ##B## in an electromagnetic wave. I'll let you fill in that step!

Different books, or even different points in the same book, may be talking about different kinds of energy density (instantaneous versus average), and sometimes you have to read carefully to see which is which. The mathematical notation may not always be consistent, unfortunately.
 
Last edited:
Oh Ok. Thanks for your help!
 

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