Confusion about the notation of transpose

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Discussion Overview

The discussion revolves around the notation of transpose in the context of a partitioned matrix defined as $$Z= \begin{pmatrix} 0 & A \\ B^T & T \end{pmatrix}$$. Participants explore the implications of defining matrices $A$, $B$, and $T$, particularly focusing on the meaning of $B^T$ and the notation used for $T$. The scope includes technical clarification and notation issues in linear algebra.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • Some participants define the matrix $Z$ and clarify that $B^T$ denotes the transpose of matrix $B$, with specific dimensions for $A$, $B$, and $T$.
  • Others express confusion regarding the notation of $T$, questioning whether it represents a matrix or merely serves as a notation.
  • A participant points out a potential typo in the dimensions of matrices $A$ and $B$, emphasizing that they should be $r \times m$ matrices to align with the dimensions of $T$.
  • Another participant acknowledges the notation issue, stating that the $\textsf{T}$ for transpose is unrelated to the $T$ representing the matrix.
  • One participant expresses surprise at the notation used in a published paper, labeling it as poor.

Areas of Agreement / Disagreement

Participants generally agree on the definition of $B^T$ as the transpose of $B$ and the dimensions of the matrices involved, but there is disagreement and confusion regarding the notation of $T$ and its implications.

Contextual Notes

There are limitations regarding the clarity of notation, particularly the use of $T$ in two different contexts, which may lead to misunderstandings about its role as a matrix versus a notation.

alyafey22
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Define the following

$$Z=
\begin{pmatrix}
0 & A \\
B^T & T
\end{pmatrix}$$

where we define $A$ and $B$ as $r \times m $ matrices and $T$ is an $m \times m$ matrix with nonzero distinct indeterminates at the diagonal, that is, $T_{i,i} = t_i$.

What is the meaning of $B^T$ ?
 
Last edited:
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ZaidAlyafey said:
Define the following

$$Z=
\begin{pmatrix}
0 & A \\
B^T & T
\end{pmatrix}$$

where we define $A$ and $B$ as $m \times r $ matrices and $T$ is is an $m \times m$ matrix with nonzero distinct indeterminates at the diagonal, that is, $T_{i,i} = t_i$.

What is the meaning of $B^T$ ?
$B^{\textsf{T}}$ denotes the transpose of $B$. So if $B$ is an $r\times m$ matrix with entries $b_{ij}$ then $B^{\textsf{T}}$ is an $m\times r$ matrix whose $(i,j)$-entry is $b_{ji}.$

Notice that $A$ and $B$ should be $r\times m$ matrices, not $m\times r$. That way, $A$ has the same number of columns as $T$, and $B^{\textsf{T}}$ has the same number of rows as $T$. To complete the partitioned matrix, the $0$ in the top left corner of $Z$ represents an $r\times r$ matrix consisting of all zeros.
 
Notice that $A$ and $B$ should be $r\times m$ matrices, not $m\times r$. That way, $A$ has the same number of columns as $T$, and $B^{\textsf{T}}$ has the same number of rows as $T$

You are correct , that was a typo. But my confusion is for using $T$ as a matrix and as a transpose. I know that $B^T$ normally defines the transpose of a matrix but is $T$ in the first place a matrix ? or just a notation ?
 
ZaidAlyafey said:
But my confusion is for using $T$ as a matrix and as a transpose. I know that $B^T$ normally defines the transpose of a matrix but is $T$ in the first place a matrix ? or just a notation ?
I hadn't even noticed that! It's just a case of bad notation. The $\textsf{T}$ that denotes the transpose is nothing to do with the $T$ that denotes the matrix. I'm glad that in my previous comment I automatically used different typefaces for them.
 
I found that construction in a published paper about Linear matroid parity. I am surprised that the authors are using such a bad notation :/
 

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