1. Jun 1, 2012

### jerbeast

Hi,

Please apologize the ignorant question, but I am confused on applying the discharge capacity of a capacitor.

If Farads = Coulombs/Volt, then a hypothetical 1 Farad capacitor could generate 1 volt at 1 amp for one second. But by the same formula, a .00005 Farad capacitor could generate 20,000 volts at 1 amp for one second.

What am I missing?

Jerry

2. Jun 1, 2012

### the_emi_guy

jerbeast,
You have it correct, but your wording is a little unusual. See if this version makes more sense to you...

Starting with uncharged capacitor:

If I pump 1A of current for 1 sec into a 1F capacitor, its voltage will be pumped up to 1V.

If I pump 1A of current for 1 sec into a .00005F capacitor, its voltage will be pumped up to 20,000v.

3. Jun 1, 2012

### Staff: Mentor

Hi jerbeast! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif [Broken]

Q = CÂ·V

There is no mention of current or time in that equation.

Last edited by a moderator: May 6, 2017
4. Jun 1, 2012

### Staff: Mentor

That's a good way of looking at it. Perhaps OP could instead consider two capacitors that start off already charged. To nominate a figure, let's imagine each is pre-charged to 40kV.

Now, if you draw 1A for 1 sec from the 1F capacitor, its plate voltage will fall by just 1V, and the capacitor will still be almost fully charged, at 39,999V.
If you draw 1A for 1 sec from the .00005F capacitor, its voltage will fall by 20kV. So that capacitor will as a result become half discharged.

5. Jun 1, 2012

### jerbeast

Thanks for the quick responses. That helped considerably.