Confusion regarding surface tension direction and force balance

AI Thread Summary
The discussion centers on the confusion regarding surface tension and force balance in a scenario involving a bubble half-immersed in a liquid. Participants clarify that surface tension acts to minimize surface area and that the forces at the bubble-liquid and bubble-air interfaces need careful consideration. There is debate about the correct interpretation of contact angles, with emphasis on the need for accurate diagrams to represent the situation. The conversation highlights the importance of clear terminology, as terms like "liquid," "fluid," and "medium" can lead to misunderstandings. Ultimately, the group agrees that a proper analysis of forces, including buoyancy and adhesion, is essential for solving the problem accurately.
palaphys
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Homework Statement
Analyze the equilibrium of a liquid bubble of density sigma, such that it floats exactly half immersed in a fluid of density rho. The surface tension of the liquid is S. (You may assume that the contact angle between the fluid bubble interface is roughly 0)
Relevant Equations
F= Sl
1743763102256.png

so this is the scenario given in the question.
What I know: there are forces due to surface tension in the following interfaces, at the contact areas: bubble-liquid, bubble-air and liquid-air.

as the forces in action are in the vertical plane, I am ignoring the forces at play at the surface, which pull the liquid surface outward in the horizontal plane. ( please correct me if I am wrong. ).

I am very confused about the direction of surface tension in the fluid-bubble interface, and the air- bubble interface.
Please correct me if my interpretation of surface tension itself is incorrect, as what I have been taught is that surface tension acts to "minimize surface energy" and thus surface area. However I am unable to apply this concept here.
 
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Your diagram does not represent "the contact angle between the fluid bubble interface is roughly 0". You show it as 90°.

But the question puzzles me… I would think what we need to know is the surface tension of the medium in which the bubble is floating, not that of the bubble.
 
haruspex said:
Your diagram does not represent "the contact angle between the fluid bubble interface is roughly 0". You show it as 90°.

But the question puzzles me… I would think what we need to know is the surface tension of the medium in which the bubble is floating, not that of the bubble.
sorry about the diagram. It may be a bit inaccurate. also, we know the surface tension of the medium in which the bubble is floating. That is what I have mentioned in the question as S. Also, after a bit of thinking my intuition says that the surface tension force form the liquid must be upward, so as to minimize area contact with the surface, and likewise the surface tension force from the air(if any) must probably act downward for the same reason.

Is this right? Please let me know
 
palaphys said:
sorry about the diagram. It may be a bit inaccurate. also, we know the surface tension of the medium in which the bubble is floating. That is what I have mentioned in the question as S. Also, after a bit of thinking my intuition says that the surface tension force form the liquid must be upward, so as to minimize area contact with the surface, and likewise the surface tension force from the air(if any) must probably act downward for the same reason.

Is this right? Please let me know
I was confused by references to "liquid" and "fluid" as though these were different. I read it as a sphere of a liquid (but described as a bubble) floating on the surface of a different one (the fluid).
So, as I now understand it, we have only one liquid, with a spherical air bubble embedded in its surface. Is that right?

You still don’t seem to get the bit about zero contact angle. What do you think the join between the bubble and the surface of the surrounding liquid looks like? Try to draw a diagram in which the bubble has some thickness.
 
I too find the problem statement very confusing. Is this the exact word-for-word statement of the problem that you were given? If not, please provide the exact statement.
 
haruspex said:
I was confused by references to "liquid" and "fluid" as though these were different. I read it as a sphere of a liquid (but described as a bubble) floating on the surface of a different one (the fluid).
So, as I now understand it, we have only one liquid, with a spherical air bubble embedded in its surface. Is that right?

You still don’t seem to get the bit about zero contact angle. What do you think the join between the bubble and the surface of the surrounding liquid looks like? Try to draw a diagram in which the bubble has some thickness.
Chestermiller said:
I too find the problem statement very confusing. Is this the exact word-for-word statement of the problem that you were given? If not, please provide the exact statement.
I do not have the exact question right now. But I have modified the question a little bit here, the question mentions a BUBBLE which is exactly half immersed in another fluid, such that the bottom part is wet (that is the reason I said contact angle=0) . the question asks to determine the RADIUS of the bubble in terms of the surface tension of the FLUID, density of the bubble liquid and the same of the fluid. But to solve this an analysis of forces acting on the bubble is necessary.
 
palaphys said:
I do not have the exact question right now.
That's a pity. I agree with @haruspex and @Chestermiller. The question is (still) unclear.

You might consider re-writing the question: imagine you are someone reading the question for the first time.

For example, you refer to ‘liquid’, ‘fluid’ and ‘medium’. It’s important to use terms unambiguously and consistently. So, if two different liquids are involved, you could call them A and B, (making sure it is clear which is which).

Also, I don’t think a bubble would be spherical in these circumstances. I wonder if something is mis-translated and the ‘bubble’ is actually meant to be a solid sphere - that might make more sense.
 
Fwiw, I came to think of it as looking like a humpback bridge reflected in the river below.
The semicircular underside of the bridge and its reflection represent the inside surface of the bubble. The roadway arcs smoothly up (but soon becoming vertical) then forms a semicircle at a slightly greater radius. The nearly vertical bit, where surrounding surface transitions to bubble surface, constitutes the zero contact angle.
In this model, you can calculate the force of surface tension exerted by the surrounding liquid surface on the outer surface of the bubble and balance that against the buoyant force from the submerged half of the bubble.

But since you say you added the bit about zero contact angle, a key reason for that interpretation goes away.
 
Steve4Physics said:
That's a pity. I agree with @haruspex and @Chestermiller. The question is (still) unclear.

You might consider re-writing the question: imagine you are someone reading the question for the first time.

For example, you refer to ‘liquid’, ‘fluid’ and ‘medium’. It’s important to use terms unambiguously and consistently. So, if two different liquids are involved, you could call them A and B, (making sure it is clear which is which).

Also, I don’t think a bubble would be spherical in these circumstances. I wonder if something is mis-translated and the ‘bubble’ is actually meant to be a solid sphere - that might make more sense.
I have found a question which very closely resembles the question which I encountered:
1743904957604.png
 
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  • #10
palaphys said:
I have found a question which very closely resembles the question which I encountered:
View attachment 359516
That matches my original interpretation in post #2, and resolves the issue I flagged there: the surface tension given is that of the surrounding liquid, not of the liquid in the droplet.
So, can you now draw the diagram with the zero contact angle between the two liquids?

Btw, the question is still flawed in that it makes an unstated assumption about the units of the densities.
 
  • #11
haruspex said:
Btw, the question is still flawed in that it makes an unstated assumption about the units of the densities.
what unstated assumption do you mean?
1743930265341.png

also for zero contact angle I think the diagram above is more accurate (the one on the top left is just a reference for defining contact angle, please ignore it)
 
  • #12
palaphys said:
what unstated assumption do you mean? View attachment 359519
also for zero contact angle I think the diagram above is more accurate (the one on the top left is just a reference for defining contact angle, please ignore it)
No, that's not it.
You are told the drop is spherical and half immersed, so the surrounding liquid surface must contact it somewhere near its "equator". But the contact angle is zero, so what must that surface do near the droplet?

Oh, and there is a second flaw in the question: it has two solutions.
(No, the other "solution" I had in mind is a 180° contact angle.)
 
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  • #13
palaphys said:
I have found a question which very closely resembles the question which I encountered:
View attachment 359516
Can I add to what @haruspex has said.

Your Post #9 question might be better-written as:

"A spherical object of density ##\rho## is half immersed in a liquid of density ##\sigma## (where values of ##\rho## and ##\sigma## are to be expressed in units of kgm##^{-3}##)...".

[Edit: The Post #9 question should also say that the contact angle is approximately zero.]

You need to identify all forces (including their directions) on the sphere. Look at this diagram (taken from https://www.geeksforgeeks.org/surface-tension/):
1743947209779.jpeg

A key step is to draw a diagram for your problem and to use it to identify the direction of the force (adhesion) of the liquid on the sphere.
 
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  • #14
Steve4Physics said:
Can I add to what @haruspex has said.

Your Post #9 question might be better-written as:

"A spherical object of density ##\rho## is half immersed in a liquid of density ##\sigma## (where values of ##\rho## and ##\sigma## are to be expressed in units of kgm##^{-3}##)...".

You need to identify all forces (including their directions) on the sphere. Look at this diagram (taken from https://www.geeksforgeeks.org/surface-tension/):View attachment 359524
A key step is to draw a diagram for your problem and to use it to identify the direction of the force (adhesion) of the liquid on the sphere.
I think that the surface tension force from the liquid of density ##\sigma## acts in an upward direction, as surface tension minimizes surface area in contact. In addition to that, there would be a buoyant force and a weight force. Balancing these would give me the answer. correct?
 
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  • #15
haruspex said:
No, that's not it.
You are told the drop is spherical and half immersed, so the surrounding liquid surface must contact it somewhere near its "equator". But the contact angle is zero, so what must that surface do near the droplet?

Oh, and there is a second flaw in the question: it has two solutions.
the surface near the droplet must be flat like this right? the contact angle being zero means that the bubble is ''wetted'' right?
 
  • #16
palaphys said:
I think that the surface tension force from the liquid of density ##\rho## acts in an upward direction,
That's confusing. Do you mean 'from the liquid of density ##\sigma##'?

Note that the force at the boundary between the sphere and liquid is called adhesion; it is incorrect to call it surface tension.

At the boundary:
a) the liquid exerts a force of adhesion on the sphere;
b) the sphere exerts a force of adhesion on the liquid.
These two forces have equal magnitudes and opposite directions (Newton's 3rd law). The liquid is being pulled in one direction and the sphere is being pulled the opposite direction.

A suitable diagram helps you find the directions of the two forces - which is why you are being encouraged to present a diagram!

palaphys said:
as surface tension minimizes surface area in contact.
If you have a single liquid, surface tension minimises its surface area. That's not relevant here.

palaphys said:
In addition to that, there would be a buoyant force and a weight force. Balancing these would give me the answer. correct?
Yes! You will find it best to work with symbols: use 'g' for acceleration due to gravity and 'S' for surface tension. Don't use numerical values till the end.
 
  • #17
Steve4Physics said:
That's confusing. Do you mean 'from the liquid of density ##\sigma##'?

Note that the force at the boundary between the sphere and liquid is called adhesion; it is incorrect to call it surface tension.

At the boundary:
a) the liquid exerts a force of adhesion on the sphere;
b) the sphere exerts a force of adhesion on the liquid.
These two forces have equal magnitudes and opposite directions (Newton's 3rd law). The liquid is being pulled in one direction and the sphere is being pulled the opposite direction.

A suitable diagram helps you find the directions of the two forces - which is why you are being encouraged to present a diagram!


If you have a single liquid, surface tension minimises its surface area. That's not relevant here.


Yes! You will find it best to work with symbols: use 'g' for acceleration due to gravity and 'S' for surface tension. Don't use numerical values till the end.
1. yes, I meant sigma. (edited now)
2. You say there are forces of adhesion in action. But what about surface tension forces then? (at the interface)
3. How do I determine the direction of the adhesion forces here intuitively?
 
  • #18
palaphys said:
2. You say there are forces of adhesion in action. But what about surface tension forces then? (at the interface)
I was overcomplicating things. Sorry. Surface tension and adhesion, (and also cohesion and capillary force) are useful terms - you can read about them for yourself.

So forget about adhesion. Go bck to thinking in terms of weight, upthrust and surface tension force.

palaphys said:
How do I determine the direction of the adhesion [surface tension] forces here intuitively?
1) Draw a diagram, making sure the meniscus shows the correct contact angle.

2) Look at the shape of the meniscus.

3) Is the meniscus above or below the main liquid level? If the mensicus is above the main liquid level, it's because the sphere is pulling the liquid up. Corespondingly if the meniscus is below the main liquid level. Then apply Newton's 3rd law to get the direction of the force on the sphere.

Minor edit.
 
  • #19
Steve4Physics said:
I was overcomplicating things. Sorry. Surface tension and adhesion, (and also cohesion and capillary force) are useful terms - you can read about them for yourself.

So forget about adhesion. Go bck to thinking in terms of weight, upthrust and surface tension force.


1) Draw a diagram, making sure the meniscus shows the correct contact angle.

2) Look at the shape of the meniscus.

3) Is the meniscus above or below the main liquid level? If the mensicus is above the main liquid level, it's because the sphere is pulling the liquid up. Corespondingly if the meniscus is below the main liquid level. Then apply Newton's 3rd law to get the direction of the force on the sphere.

Minor edit.
2. where is the meniscus here? are you talking about the one which is above the main liquid level? as the spherical object is fully wetted I think there is no meniscus below the liquid level.
This seems to imply that the surface tension is downward. But the solution to the problem suggests otherwise.
 
  • #20
palaphys said:
2. where is the meniscus here?
The meniscus in this problem is the curved liquid surface where the liquid meets the sphere's equator (at the sphere-liquid-air boundary). A cross-sectional view (with contact angle about zero) looks like this:
1744040583878.png


palaphys said:
This seems to imply that the surface tension is downward. But the solution to the problem suggests otherwise.
The force on the sphere (from the surface tension effect) is downwards.

The circumference of the sphere's equator has length ##2\pi R##. If ##S## is the surface tension and ##\theta## is the contact angle, then the downwards force on the sphere from the surface tension effect is ##2\pi R S \cos(\theta)##. If you are not clear where this formula comes from, read-up/research capillary action for yourself, as it is closely related.
 
  • #21
Steve4Physics said:
The meniscus in this problem is the curved liquid surface where the liquid meets the sphere's equator (at the sphere-liquid-air boundary). A cross-sectional view (with contact angle about zero) looks like this:
View attachment 359565


The force on the sphere (from the surface tension effect) is downwards.

The circumference of the sphere's equator has length ##2\pi R##. If ##S## is the surface tension and ##\theta## is the contact angle, then the downwards force on the sphere from the surface tension effect is ##2\pi R S \cos(\theta)##. If you are not clear where this formula comes from, read-up/research capillary action for yourself, as it is closely related.
1744085273299.png

this is the given solution. Is it incorrect? Very confused now.
 
  • #22
palaphys said:
View attachment 359585
this is the given solution. Is it incorrect? Very confused now.

At last, that clarifies the intent. It seems the author omitted to mention that the contact angle is 180°. The diagram in post #20 is correct except that the meniscus curves the wrong way: it should dip down to meet the droplet, not up.
 
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  • #23
haruspex said:
At last, that clarifies the intent. It seems the author omitted to mention that the contact angle is 180°. The diagram in post #20 is correct except that the meniscus curves the wrong way: it should dip down to meet the droplet, not up.
Okay, now I am a bit more clear, but still got some doubts . How do I accurately predict the direction of surface tension in ANY case, and what is the formal definition of contact angle? how exactly to measure that?

Also, what is the logic behind the fact that the direction of the meniscus helps in finding the direction of surface tension?
Why is the fact that ''surface tension aids in minimizing surface energy and hence surface area'' not useful here?
 
  • #24
palaphys said:
Okay, now I am a bit more clear, but still got some doubts . How do I accurately predict the direction of surface tension in ANY case, and what is the formal definition of contact angle? how exactly to measure that?
https://en.wikipedia.org/wiki/Contact_angle
palaphys said:
Also, what is the logic behind the fact that the direction of the meniscus helps in finding the direction of surface tension?
The force from surface tension acts parallel to the surface and normally to the boundary of the surface.
palaphys said:
Why is the fact that ''surface tension aids in minimizing surface energy and hence surface area'' not useful here?
It does not help here, except to say that the surface is trying to shrink, so is pulling on its boundary. It does determine the three dimensional shape of the meniscus.
 
  • #25
haruspex said:
https://en.wikipedia.org/wiki/Contact_angle

The force from surface tension acts parallel to the surface and normally to the boundary of the surface.

It does not help here, except to say that the surface is trying to shrink, so is pulling on its boundary. It does determine the three dimensional shape of the meniscus.
1744101048755.png

In this diagram, I have constructed a tangent. Where is the contact angle? Unable to find it even after briefly going through the wiki page.
 
  • #26
To follow-up what @haruspex said:
- the Post #1 problem says the contact angle is "roughly 0";
- the problem in Post #9 does not give any contact angle;
- the solution in Post #21 applies when the contact angle is 180##^o##.
Argh!

palaphys said:
View attachment 359588
In this diagram, I have constructed a tangent. Where is the contact angle? Unable to find it even after briefly going through the wiki page.
Contact angles are usually shown for a meniscus meeting a flat surface. But in your problem, the meniscus meets a curved surface (the sphere). So you need to consider the angle between 2 tangents:

1744104801748.png


The red line is the tangent to the sphere where it meets the meniscus. (With the sphere half submerged, this line is vertical.)

The blue line is the tangent to the meniscus where it meets the sphere.

The contact angle (##\theta##) is the angle between them.

It's a useful exercise to visualise what happens as ##\theta## varies from 0 to 180##^o##.

In the above diagram the meniscus is being pulled upwards by the sphere. Therefore (Newton's 3rd law) the sphere is being pulled downwards by the liquid. This is true for ##\theta \lt 90^o##.
 
  • #27
palaphys said:
Homework Statement: Analyze the equilibrium of a liquid bubble of density sigma, such that it floats exactly half immersed in a fluid of density rho. The surface tension of the liquid is S. (You may assume that the contact angle between the fluid bubble interface is roughly 0)
Relevant Equations: F= Sl

View attachment 359445
so this is the scenario given in the question.
What I know: there are forces due to surface tension in the following interfaces, at the contact areas: bubble-liquid, bubble-air and liquid-air.

as the forces in action are in the vertical plane, I am ignoring the forces at play at the surface, which pull the liquid surface outward in the horizontal plane. ( please correct me if I am wrong. ).

I am very confused about the direction of surface tension in the fluid-bubble interface, and the air- bubble interface.
Please correct me if my interpretation of surface tension itself is incorrect, as what I have been taught is that surface tension acts to "minimize surface energy" and thus surface area. However I am unable to apply this concept here.
Surface tension is like pulling to make less contact. It pulls up at the bubble liquid interface and down at the air bubble one, and it balances everything out vertically. Basically it’s just trying to shrink the exposed surface area.
 
  • #28
RicoGerogi said:
Surface tension is like pulling to make less contact. It pulls up at the bubble liquid interface and down at the air bubble one, and it balances everything out vertically. Basically it’s just trying to shrink the exposed surface area.
this is what I thought. But I was told that this is a (possibly) incorrect interpretation.
 
  • #29
Steve4Physics said:
To follow-up what @haruspex said:
- the Post #1 problem says the contact angle is "roughly 0";
- the problem in Post #9 does not give any contact angle;
- the solution in Post #21 applies when the contact angle is 180##^o##.
Argh!


Contact angles are usually shown for a meniscus meeting a flat surface. But in your problem, the meniscus meets a curved surface (the sphere). So you need to consider the angle between 2 tangents:

View attachment 359591

The red line is the tangent to the sphere where it meets the meniscus. (With the sphere half submerged, this line is vertical.)

The blue line is the tangent to the meniscus where it meets the sphere.

The contact angle (##\theta##) is the angle between them.

It's a useful exercise to visualise what happens as ##\theta## varies from 0 to 180##^o##.

In the above diagram the meniscus is being pulled upwards by the sphere. Therefore (Newton's 3rd law) the sphere is being pulled downwards by the liquid. This is true for ##\theta \lt 90^o##.
But, it seems impossible to visualize a 0 degree or 180 degree contact angle. What would be the difference between the two, and what do they physically imply?
 
  • #30
@Steve4Physics
1744111570644.png

is this an accurate diagram? As the meniscus becomes flatter and flatter, eventually the contact angle seems to tend to 180. I do not understand how this is different from a zero contact angle
 
  • #31
palaphys said:
@Steve4Physics View attachment 359594
is this an accurate diagram? As the meniscus becomes flatter and flatter, eventually the contact angle seems to tend to 180. I do not understand how this is different from a zero contact angle
ohh I get it now, this diagram is incorrect. rather,
1744113131426.png

this must be the right way of representing an obtuse contact angle.
 
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  • #32
palaphys said:
@Steve4Physics View attachment 359594
is this an accurate diagram? As the meniscus becomes flatter and flatter, eventually the contact angle seems to tend to 180. I do not understand how this is different from a zero contact angle
The contact angle is measured through the liquid, not through the air.
Water in a vertical capillary tube reaches up the sides of the tube forming a vanishingly thin collar. That is a (near) zero contact angle.
Mercury in a dish bulges upwards. Measuring from dish to surface of mercury through the mercury yields an angle of 135°.
 
  • #33
palaphys said:
@Steve4Physics View attachment 359594
is this an accurate diagram? As the meniscus becomes flatter and flatter, eventually the contact angle seems to tend to 180. I do not understand how this is different from a zero contact angle
1744113854102.png

In the above diagram:
Contact angle is about zero.
Liquid is pulled upwards by sphere.
So (Newton’s 3rd law), sphere is pulled downwards by liquid.
I.e. force on sphere is downwards.
______________________________________________

1744114260507.png

In the above diagram:
Contact angle is about 180##^o##..
Liquid is pushed downwards by sphere.
So (Newton’s 3rd law), sphere is pushed upwards by liquid.
I.e. force on sphere is upwards.
 
  • #34
Steve4Physics said:
View attachment 359596
In the above diagram:
Contact angle is about zero.
Liquid is pulled upwards by sphere.
So (Newton’s 3rd law), sphere is pulled downwards by liquid.
I.e. force on sphere is downwards.
______________________________________________

View attachment 359597
In the above diagram:
Contact angle is about 180##^o##..
Liquid is pushed downwards by sphere.
So (Newton’s 3rd law), sphere is pushed upwards by liquid.
I.e. force on sphere is upwards.
Steve4Physics said:
View attachment 359596
In the above diagram:
Contact angle is about zero.
Liquid is pulled upwards by sphere.
So (Newton’s 3rd law), sphere is pulled downwards by liquid.
I.e. force on sphere is downwards.
______________________________________________

View attachment 359597
In the above diagram:
Contact angle is about 180##^o##..
Liquid is pushed downwards by sphere.
So (Newton’s 3rd law), sphere is pushed upwards by liquid.
I.e. force on sphere is upwards.
Okay, now this is much more clearer. I still have another question. What about the other interfacial surface tensions, like the solid-air interfacial tension and the liquid-air interfacial tensions? Asking in a sense similar to this
1744116046068.png
 
  • #35
palaphys said:
Okay, now this is much more clearer. I still have another question. What about the other interfacial surface tensions, like the solid-air interfacial tension and the liquid-air interfacial tensions? Asking in a sense similar to this
View attachment 359601
Don't know what what the question means. Simply asking "What about ..." is too vague. What exactly do you want to know?

Note that there is no such thing s 'interfacial surface tension'.

Surface tension is a property of a single substance.

The interfacial force between different substances is called the interfacial tension (not interfacial surface tension).

Not something I know much about, so will leave thread at this point.
 
  • #36
Steve4Physics said:
Don't know what what the question means. Simply asking "What about ..." is too vague. What exactly do you want to know?

Note that there is no such thing s 'interfacial surface tension'.

Surface tension is a property of a single substance.

The interfacial force between different substances is called the interfacial tension (not interfacial surface tension).

Not something I know much about, so will leave thread at this point.
What exactly I want to know, is the about the pairs of surface tension forces between liquid gas, solid gas etc
as shown in the picture below, but in the context of the present problem (of sphere in liquid with contact angle roughly 180)

1744123924896.png
 
  • #37
palaphys said:
this is what I thought. But I was told that this is a (possibly) incorrect interpretation.
Please ask from that person how is this incorrect interpretation...
 
  • #40
Alright, so what I think is that, only the S_lg meaningfully contributes to a mechanical force, as in this case, it is the only deformable meniscus. all the other interfacial surface tensions only contribute to surface energy. I would like it if someone refines my understanding on this.
 
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