Congruence with numbers with exponents on top of exponents

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Homework Help Overview

The problem involves calculating the expression 2 + 3^2 + 5^3 + (3^{2*5})^3 in the context of modular arithmetic, specifically modulo 15. The original poster expresses confusion regarding the handling of large exponents and congruences.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the interpretation of the expression, particularly the handling of the term (3^{2*5})^3. Questions arise about evaluating large numbers in modular arithmetic and whether there are methods to simplify calculations.

Discussion Status

The discussion is ongoing with participants clarifying the expression and exploring methods to evaluate large exponents under modulo constraints. Some guidance has been offered regarding the use of calculators and potential simplifications, but no consensus has been reached on the best approach.

Contextual Notes

There is uncertainty regarding the interpretation of the exponent notation, with some participants suggesting alternative interpretations that could affect the calculations. The original poster is working independently and may have constraints based on the resources available to them.

morrowcosom
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Homework Statement



Calculate 2 + 3^2 + 5^3 + 3^2*5^3 in Z15
(That last group of numbers means 3 to the 2*5 power then take this answer to the third power, It just did not paste like that)

Homework Equations





The Attempt at a Solution



2+9+5+3<--the 3 is a random guess, because I am totally lost what do to do with this last number.
I am doing this problem for independent study off of a website and it says the answer is 9, which means the last answer must be 8. How do you deal with congruence when there are such large numbers with multiple exponents like those created by the last sequence of numbers in the problem (3^2*5^3, which means take 3 to the 2*5 power then take this answer to the third power)) ?

 
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First off, just to clarify, you do mean [itex]2 + 3^2 + 5^3 + (3^{2*5}) ^ {3} in Z_{15}[/itex], right?
 
If this is so, then you should know at least what [itex](3^{2*5})^{3}[/itex] evaluates to...
 
My problem is that I cannot figure out what the above number evaluates to congruence wise. It is so huge when you figure it up that it will not fit into a calculator. Is their some procedure to shrink this number or these exponents down to size, or figure out how the number compares to the mod by looking at?
 
morrowcosom said:
My problem is that I cannot figure out what the above number evaluates to congruence wise. It is so huge when you figure it up that it will not fit into a calculator. Is their some procedure to shrink this number or these exponents down to size, or figure out how the number compares to the mod by looking at?

The EE button on your calculator might be useful here.
http://mathforum.org/library/drmath/view/54346.html
 
Just the caculator that comes with "Windows" gives [itex]3^{2*5}= 3^{10}= 59049[/itex], not all that big! Find what that is congruent to modulo 15 and raise that to the 3 rd power.

(For that matter, [itex]\left(3^{10}\right)^3[/itex] is NOT too big to be done exactly on any decent calculator.)
 
Maybe he means [tex]3^{2.5^3}[/tex] ? This would explain why it's too big for his calculator, because(310)3[itex]\approx[/itex]10^14 should be doable for any calculator made in this millenium :wink:

morrowcosom said:
It is so huge when you figure it up that it will not fit into a calculator.
 
morrowcosom said:
(That last group of numbers means 3 to the 2*5 power then take this answer to the third power, It just did not paste like that)

That's what he said, so I'm assuming that we were on the right track.
 

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