Conjecture: Limit Formula for n Approaching Infinity

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SUMMARY

The limit formula discussed is lim_{n→∞} (√n / 2^(2n)) * ((2n)! / (n!)^2) = 1/√π. The proof of this limit can be approached using Stirling's approximation, which provides a way to estimate factorials for large values of n. The discussion emphasizes the need for a rigorous proof to establish that the limit is strictly between zero and infinity.

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jostpuur
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I have some reasons to believe that this equation is true:

[tex] \lim_{n\to\infty} \frac{\sqrt{n}}{2^{2n}} \frac{(2n)!}{(n!)^2} = \frac{1}{\sqrt{\pi}}[/tex]

Anyone having idea of the proof? I don't even know how to prove that the limit is strictly between zero and infinity.
 
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I can do it with Stirlings approximation.
 
ok. Thank's for reminding of it.
 

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