1. The problem statement, all variables and given/known data Two blocks are arranged at the ends of a massless string as shown in the figure. The system starts from rest. When the 2.33 kg mass has fallen through 0.315 m, its downward speed is 1.31 m/s. The acceleration of gravity is 9.8 m/s^2. What is the frictional force between the 3.81kg mass and the table? Answer in units of N. 2. Relevant equations ΣF=ma Ff=μFn v2-u2=2ax 3. The attempt at a solution First, I found the acceleration of the system by using the formula v2-u2=2ax. 1.312-o2=2a*0.315 a=2.723 m/s^2 I then multiplied the mass of the block on the table by the acceleration because F=ma F=3.81(2.723) F=10.378 I tried this answer, but it was wrong. I have no idea how to do this problem, but this is what I got to looking through my textbook and online. If anyone would explain how to get started solving it on the right track, I'd be extremely grateful. Thanks!