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Conservation of Angular Momentum and Uniform Rod

  1. Mar 6, 2009 #1
    1. The problem statement, all variables and given/known data
    A small 0.157 kg block slides down a frictionless surface through height h = 0.307 m and then sticks to a uniform vertical rod of mass M = 0.397 kg and length d = 2.78 m. The rod pivots about point O through angle θ before momentarily stopping. Find θ.


    2. Relevant equations
    Equation 1: I= (1/3)Md^2 + md^2
    Equation 2: v=(2gh)^(1/2)
    Equation 3: W=m(block)dv/I
    Equation 4: arccos(1 -(I*W^2/[d*g(2m + M) ]))

    [I and W are for the road and block system]


    3. The attempt at a solution
    Using equation 1, I found I to be 0.02727 kg*m^2. Then I found W to be 4.3357 using equation 2 and 3. I then plugged in the values into equation 4 and got 40.50412 degrees, but apparently I'm doing something wrong.
     
  2. jcsd
  3. Mar 6, 2009 #2
    Nevermind!
     
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