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Conservation of (Angular) Momentum

  1. Jan 10, 2007 #1
    The problem is "A wooden block of mass m slides with an initial speed of vi up a straight incline that makes an angle of theta with the horizontal. If the incline is rough with a coefficient of kinetic friction uk, determine the maximum height it rises in terms of h found in part a (which was H = vi^2/2g)"

    So what I did was conservation of energy. KE at the bottom = PE at the top + Work.
    mgh + Fd = 1/2mv^2
    h = [mvi^2 - ukmgcos(theta)d]/mg
    pPoblem is, I don't know what d is and it can't be part of my final answer. I know it's the distance that the block travels up the ramp, but how do I figure that out.
    Also, since it says in terms of h found in part a, does that mean I set everything equal to vi^2/2g?

    How would I do this with a hoop with radius R?
  2. jcsd
  3. Jan 10, 2007 #2
    Sorry. Realize this is in the wrong spot.
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