Conservation of Energy on Current-Carrying Wire in Magnetic Field

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SUMMARY

The discussion centers on the conservation of energy in a current-carrying wire within a magnetic field, specifically analyzing the relationship between force, work, and electrical energy input. The force on a wire is calculated using the formula F = IL x B, where I is current, L is length, and B is magnetic field strength. When the magnetic field strength is doubled, the work done on the wire increases from 1BX to 3BX joules, despite the electrical energy input remaining constant at E = IVT. This discrepancy raises questions about the source of the additional energy, suggesting a need for a deeper analysis using differential equations.

PREREQUISITES
  • Understanding of the Lorentz force law (F = IL x B)
  • Basic knowledge of electrical energy calculations (E = IVT)
  • Familiarity with magnetic fields and their properties
  • Introduction to differential equations for system analysis
NEXT STEPS
  • Explore the implications of the Lorentz force in electromagnetic systems
  • Study the principles of work and energy in magnetic fields
  • Investigate differential equations in the context of electromagnetic theory
  • Examine the behavior of magnetic fields under varying conditions and their effects on current-carrying conductors
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and researchers interested in electromagnetism and energy conservation principles in electrical systems.

yosimba2000
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So force on a current carrying wire = ILxB.

If I have a bunch of bar magnets making a uniform magnetic field of strength B, then a 1 meter long wire of 0 ohms carrying 1 Amp, the force on that wire is (1)(1)xB = 1B. If I let that force move the wire for a time T, let's assume the wire moved a distance X. So the work done on the wire is 1BX joules.

Now let's say I keep everything the same but double the magnetic field using stronger magnets. So now Force on this wire is (1)(1)(2B) = 2B. Since the force is double the original and acting on the same object, if I let it act upon the wire for the same amount of time T, the wire will move a longer distance than the original X, let's say 1.5X. So the work done on this wire is (2B)(1.5X) = 3BX joules.

My electrical energy input was the same in both scenarios: E = IVT. I, V, and T were the same in both experiments, but the energy exerted on the wires were different by a factor of 3. How? I understand the force is larger, but how did I get 1BX and 3BX joules of energy for the same electrical input? It must have come from somewhere, but where? It's not as though the magnets "lost" magnetic energy and became less magnetic.
 
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I suggest you can try to describe your system with differential equations. :smile:
 
yosimba2000 said:
I, V, and T were the same in both experiments
Are you sure about that?
 
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