1. The problem statement, all variables and given/known data A ball of mass M and radius R has a moment of inertia of I =2/5MR. The ball is released from rest and rolls down the ramp with no frictional loss of energy. The ball is projected vertically upward o a ramp as shown in the diagram, reaching a maximum height ymax above the point where it leaves the ramp. Determine the maximum height of the projectile ymax in terms of h The image is cut off but h is the height from the top of the ramp to the ball 2. Relevant equations PE=1/2mv^2 Rotational KE= 1/2 I omega^2 KE= 1/2mv^2 3. The attempt at a solution Using x as the distance between the bottom and top of the ramp: mg(h+x) = 1/2mv^2+1/2I omega^2 =1/2mv^2 + 1/2(2/5mr^2)omega^2 = 1/2mv^2 + 1/5mv^2 = 7/10mv^2 7/10mv^2=mgx + 1/2mv'^2 1/2mv'^2 = ymax im stuck here D: any hints?